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Timeline for Fermionic partition function

Current License: CC BY-SA 3.0

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Apr 4, 2018 at 10:28 comment added Giuseppe I mean this is by definition, the resolution of identity you gave are relations which are for ONLY for coherent states the exponential comes from the fact that coherent states are not normalized etc , i really advise you to take a look on the book i gave you, this is not so difficult you can prove that you have this expression for the closure relation and everything else
Apr 4, 2018 at 10:12 comment added user I am not sure why can we use coherent states here, what ensures that we can write $\psi, \bar \psi$ as coherent states?
Apr 4, 2018 at 10:08 comment added Giuseppe I don't understand your question, if you're asking why we use coherent states, for me it's just because it simplifies things in some cases, for example if you try to solve the Harmonic oscillator with path integral, it is much more easy with coherent states. You can also do that in the usual (x,p) representation of path integral but it's longer and more difficult.
Apr 4, 2018 at 4:51 comment added user Thanks. Are always eigenvalues of the form of coherent states?
Apr 3, 2018 at 15:20 history edited AccidentalFourierTransform CC BY-SA 3.0
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Apr 3, 2018 at 14:55 comment added Giuseppe By the way if you want a good book which rigourously explains this, take a look on the book " Path integrals in quantum mechanics" of Jean Zinn-Justin, this is an amazing introduction
Apr 3, 2018 at 14:52 history answered Giuseppe CC BY-SA 3.0