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Mar 16, 2018 at 10:02 history edited Christophe CC BY-SA 3.0
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Mar 16, 2018 at 9:50 comment added Christophe In the usual derivation of the Boltzmann distribution, one introduces a discretization of the phase space. The microscopic states are then countable. $h_0$ is the surface of a cell (one degree of freedom). $e^{-\beta E}/{\cal Z}$ is the probability of a microscopic state so dividing by $h_0$, you get a probability density. You can usually safely ignore it since in the above expressions, $h_0$ also appears in the partition function so they cancel in the final expression.
Mar 16, 2018 at 9:43 comment added Student This is excellent, thank you! May I ask, what is $h_0$? (Sorry, I am obviously not a physicist!)
Mar 16, 2018 at 9:40 vote accept Student
Mar 16, 2018 at 9:24 history answered Christophe CC BY-SA 3.0