Timeline for What will be the trajectory of the given motion [closed]
Current License: CC BY-SA 4.0
17 events
| when toggle format | what | by | license | comment | |
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| Sep 13, 2018 at 8:36 | history | edited | Aumkaar Pranav | CC BY-SA 4.0 |
Improved the question and removed minor errors
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| Sep 12, 2018 at 13:33 | comment | added | Aumkaar Pranav | @sammygerbil No, it is not a duplicate of the said question. | |
| Sep 12, 2018 at 13:33 | comment | added | Aumkaar Pranav | @Qmechanic PS: I have edited the question in order to improve it. However I still can not share my work on this question as I had asked the question almost 6 months ago and now I can not find where I tried solving it. Sincerely sorry for that. | |
| Sep 12, 2018 at 13:32 | history | edited | Aumkaar Pranav | CC BY-SA 4.0 |
I tried improving the question so that I do not get banned from asking further questions.
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| Feb 26, 2018 at 10:42 | vote | accept | Aumkaar Pranav | ||
| Feb 13, 2018 at 19:47 | history | closed |
Kyle Kanos Chris♦ Jon Custer sammy gerbil Emilio Pisanty |
Not suitable for this site | |
| Feb 13, 2018 at 16:59 | comment | added | sammy gerbil | Possible duplicate of Circular motion - vectors | |
| Feb 12, 2018 at 15:40 | comment | added | John Alexiou | @AumkaarPranavShukla - oh yeah, the mobile app does not render MathJax. The math renders to this image. | |
| Feb 12, 2018 at 13:53 | comment | added | Aumkaar Pranav | @ja72 I use the SE Android app. | |
| Feb 11, 2018 at 17:48 | comment | added | John Alexiou | @AumkaarPranavShukla - I am sorry to hear that MathJax doesn't render properly for you. Physics supports math objects in posts and comments, so my guess is that there is something with the browser or the firewall that prevents proper rendering. | |
| Feb 11, 2018 at 3:42 | comment | added | Aumkaar Pranav | @ja72 All I can read in your comment is a mess of symbols. I think the app of SE doesn't convert those symbols into the actual mathematical terms when use them in comments. | |
| Feb 9, 2018 at 22:41 | review | Close votes | |||
| Feb 13, 2018 at 19:47 | |||||
| Feb 9, 2018 at 19:48 | answer | added | ndrearu | timeline score: 5 | |
| Feb 9, 2018 at 19:44 | comment | added | John Alexiou | You need a mathematical proof of the following velocity/acceleration decomposition $$ \begin{aligned} \mathbf{v} & = v \mathbf{e} \\ \mathbf{a} & = \dot{v} \mathbf{e} + \frac{v^2}{r} \mathbf{n} \end{aligned} $$ where $\mathbf{e}$ is the tangential direction and $\mathbf{n}$ the normal direction vectors. Here $r$ is the radius of curvature of the path, and $v$ and $\dot{v}$ the speed and speed rate. | |
| Feb 9, 2018 at 18:27 | comment | added | Qmechanic♦ | Hi Aumkaar Pranav Shukla. If you haven't already done so, please take a minute to read the definition of when to use the homework-and-exercises tag, and the Phys.SE policy for homework-like problems. | |
| Feb 9, 2018 at 18:26 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
added 4 characters in body; edited tags
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| Feb 9, 2018 at 17:18 | history | asked | Aumkaar Pranav | CC BY-SA 3.0 |
