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Dec 21, 2017 at 22:09 comment added Dave Rosenman Very interesting... I'm going to have to pull out Griffith's book over the weekend and do a bit of reviewing... Haven't studied electrostatics since I graduated in May.
Dec 21, 2017 at 18:35 comment added Emilio Pisanty The potential $V(x,y,z) = V_0 xy$ is a perfectly valid electrostatic potential, and it can very naturally be seen as having two equipotential surfaces (the $yz$ plane and the $xz$ plane) that intersect along a line.
Dec 20, 2017 at 18:08 comment added ymuf Unless the field is zero at the point of intersection?
Dec 20, 2017 at 17:57 history answered Dave Rosenman CC BY-SA 3.0