Timeline for Why is electric field zero where equipotential surfaces intersect?
Current License: CC BY-SA 3.0
15 events
| when toggle format | what | by | license | comment | |
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| Dec 22, 2017 at 9:30 | history | protected | Qmechanic♦ | ||
| Dec 22, 2017 at 9:21 | history | edited | Emilio Pisanty |
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| Dec 21, 2017 at 21:49 | vote | accept | ymuf | ||
| Dec 21, 2017 at 21:48 | vote | accept | ymuf | ||
| Dec 21, 2017 at 21:49 | |||||
| Dec 21, 2017 at 20:09 | answer | added | ProfRob | timeline score: 1 | |
| Dec 21, 2017 at 19:42 | answer | added | Emilio Pisanty | timeline score: 6 | |
| Dec 21, 2017 at 2:21 | answer | added | Alfred Centauri | timeline score: -1 | |
| Dec 20, 2017 at 18:45 | answer | added | Jaysam | timeline score: 0 | |
| Dec 20, 2017 at 18:03 | comment | added | ymuf | Imagine a p-orbital shaped equipotential surface what would be the direction of field at the centre of it. | |
| Dec 20, 2017 at 18:00 | comment | added | Steeven | What do you mean by two equipotential surfaces of the same potential? If they had the same potential, then we would not call them different. We would say that they are two pieces of the same equipotential surface. Maybe this is actually a matter or words? | |
| Dec 20, 2017 at 17:58 | comment | added | ymuf | Can there also be two equipotential surfaces of the same potential that do not touch? Also, can you please answer my first question. | |
| Dec 20, 2017 at 17:57 | answer | added | Dave Rosenman | timeline score: 0 | |
| Dec 20, 2017 at 17:55 | comment | added | Steeven | "Why can't there just be two different equipotential surfaces with the same potential that intersect or touch?" Because if they are different, then they have different potentials. If they had the same potential, then they would be the same equipotential surface. | |
| Dec 20, 2017 at 17:48 | history | edited | Qmechanic♦ |
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| Dec 20, 2017 at 17:44 | history | asked | ymuf | CC BY-SA 3.0 |