Timeline for Form of Schrödinger equation for the probability density
Current License: CC BY-SA 3.0
8 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Apr 29 at 19:17 | comment | added | user56834 | It seems there are missing $\hbar$ here? See this answer: physics.stackexchange.com/a/812408/127307 | |
Dec 5, 2023 at 4:00 | comment | added | Sidharth Ghoshal | This is a very nice answer. I wanted to mention that while we shouldn’t expect $\rho$ to recover the entire quantum state it’s still very surprising we can’t even get a single PDE for $\rho$ | |
Sep 21, 2019 at 9:48 | vote | accept | Jan Bos | ||
Feb 8, 2018 at 14:51 | comment | added | AccidentalFourierTransform | @MikeFlynn Bohm wrote several books himself, so you should definitely check them out. I've heard they are quite good (even by those that dislike Bohm's interpretation). | |
Feb 8, 2018 at 5:26 | comment | added | Mike Flynn | any books on this? It's more mathematically cumbersome but I like this so much better conceptually. | |
Dec 7, 2017 at 14:22 | comment | added | Jan Bos | Appreciate the link to the Quantum Hamilton-Jacobi Equation (the 2nd differential equation in the couples set). There seems to be some work done on that but it seems not straightforward. | |
Dec 7, 2017 at 12:55 | comment | added | Jan Bos | Shouldn't the answer then be along the lines of "Yes you can but the equation involves a complicated functional of $\rho$ and is not practical to use". In fact, the 2nd part of your answer seems to contradict the first part since you showed that the degrees of freedom are coupled albeit in a complicated way. It is interesting that the relative simple probability density of say a 1s electron in hydrogen is a solution of this very tedious equation. | |
Dec 7, 2017 at 10:57 | history | answered | AccidentalFourierTransform | CC BY-SA 3.0 |