Skip to main content
15 events
when toggle format what by license comment
Feb 15, 2018 at 8:38 answer added energy storage timeline score: 0
Nov 11, 2017 at 18:10 answer added user175013 timeline score: 0
Nov 10, 2017 at 21:31 history edited Qmechanic
edited tags
Nov 10, 2017 at 21:13 comment added safesphere Javier is correct. On your diagrams you need to include an internal resistance of the battery as a resistor in series with the battery. This would solve your puzzle. I've made a 5V battery of two 3500F ultra capacitors with the total internal resistance of 0.5mOhm that can supply a current over 1000A. I've tested shorting it with a thick copper wire. The wire was instantly burnt and vaporized with drops of melted metal around. Conceptually, with this battery in your circuit, the LED would stay on.
Nov 10, 2017 at 21:09 answer added Chris timeline score: 1
Nov 10, 2017 at 21:09 vote accept GameDevFox
Nov 10, 2017 at 21:09 history edited GameDevFox CC BY-SA 3.0
Asked better question
Nov 10, 2017 at 21:05 answer added GRB timeline score: 2
Nov 10, 2017 at 21:04 comment added user93237 "Shouldn't the path with the LED still have the same amount of current, based on it's resistance, whether the extra wire is there or not?"- Yes, your simulation is correct for an ideal battery. There should be the same amount of current through the LED regardless of whether the shorting wire is there or not because the ideal battery will maintain a 5V output no matter what. In the real world, a 5V battery subjected to an extreme current drain due to a short will drop below its stated voltage and so the LED will go out.
Nov 10, 2017 at 21:01 answer added FGSUZ timeline score: 1
Nov 10, 2017 at 21:01 answer added Javier timeline score: 6
Nov 10, 2017 at 20:59 history edited GameDevFox CC BY-SA 3.0
Clarify title
Nov 10, 2017 at 20:45 history edited GameDevFox CC BY-SA 3.0
Use smaller images
Nov 10, 2017 at 20:43 review First posts
Nov 10, 2017 at 21:22
Nov 10, 2017 at 20:37 history asked GameDevFox CC BY-SA 3.0