Timeline for Square of annihilation operator
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 29, 2017 at 14:09 | vote | accept | Mazen | ||
| Oct 29, 2017 at 13:34 | comment | added | Mazen | Many thanks for your clarification. Now that is a complete answer! Honestly, I managed to prove that $<n|a^{\dagger 2}|n> = 0$ just before your post and was just about to answer my own question. But this is more comprehensive and covers the subtlty between fermionic and bosonic operators. | |
| Oct 29, 2017 at 12:04 | history | answered | Emilio Pisanty | CC BY-SA 3.0 |