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This is Neutron decay: $$n^o \to p^+ + e^- + \overline {\nu_e}.$$ and this is proton one: $$p^+ \to n^o + e^+ + \nu_e$$

so when the $e^+ =e^-$ and $\nu_e=\overline {\nu_e}$ why $n \not= p$?

my idea is that:

$$\nu_e \not= \overline {\nu_e}$$ is my theory correct?

This is Neutron decay: $$n^o \to p^+ + e^- + \overline {\nu_e}.$$ and this is proton one: $$p^+ \to n^o + e^+ + \nu_e$$

so when the $e^+ =e^-$ and $\nu_e=\overline {\nu_e}$ why $n \not= p$?

my idea is that:

$$\nu_e \not= \overline {\nu_e}$$ is my theory correct?

This is Neutron decay: $$n^o \to p^+ + e^- + \overline {\nu_e}.$$ and this is proton one: $$p^+ \to n^o + e^+ + \nu_e$$

so when the $e^+ =e^-$ and $\nu_e=\overline {\nu_e}$ why $n \not= p$?

my idea is that:

$$\nu_e \not= \overline {\nu_e}$$ is my theory correct?

I added the question "is my theory correct?" at the end to clarify the purpose of the post.
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This is Neutron decay: $$n^o \to p^+ + e^- + \overline {\nu_e}.$$ and this is proton one: $$p^+ \to n^o + e^+ + \nu_e$$

so when the $e^+ =e^-$ and $\nu_e=\overline {\nu_e}$ why $n \not= p$?

my idea is that:

$$\nu_e \not= \overline {\nu_e}$$ is my theory correct?

This is Neutron decay: $$n^o \to p^+ + e^- + \overline {\nu_e}.$$ and this is proton one: $$p^+ \to n^o + e^+ + \nu_e$$

so when the $e^+ =e^-$ and $\nu_e=\overline {\nu_e}$ why $n \not= p$?

my idea is that:

$$\nu_e \not= \overline {\nu_e}$$

This is Neutron decay: $$n^o \to p^+ + e^- + \overline {\nu_e}.$$ and this is proton one: $$p^+ \to n^o + e^+ + \nu_e$$

so when the $e^+ =e^-$ and $\nu_e=\overline {\nu_e}$ why $n \not= p$?

my idea is that:

$$\nu_e \not= \overline {\nu_e}$$ is my theory correct?

Post Closed as "Needs details or clarity" by user1504, Manishearth
Question Protected by dmckee --- ex-moderator kitten
retagged;; edited title; edited title; edited body
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Qmechanic
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Why Neutron'sis Neutron Heavier than Proton'sProton?

This is Neutron decay: $$n^o \to p^+ + e^- + \overline {\nu_e}.$$ and this is proton one: $$p^+ \to n^o + e^+ + \nu_e$$

so when the $e^+ =e^-$ and $\nu_e=\overline {\nu_e}$ why n $\not= p$$n \not= p$?

my idea is that:

$$\nu_e \not= \overline {\nu_e}$$

Why Neutron's Heavier than Proton's

This is Neutron decay: $$n^o \to p^+ + e^- + \overline {\nu_e}.$$ and this is proton one: $$p^+ \to n^o + e^+ + \nu_e$$

so when the $e^+ =e^-$ and $\nu_e=\overline {\nu_e}$ why n $\not= p$?

my idea is that:

$$\nu_e \not= \overline {\nu_e}$$

Why is Neutron Heavier than Proton?

This is Neutron decay: $$n^o \to p^+ + e^- + \overline {\nu_e}.$$ and this is proton one: $$p^+ \to n^o + e^+ + \nu_e$$

so when the $e^+ =e^-$ and $\nu_e=\overline {\nu_e}$ why $n \not= p$?

my idea is that:

$$\nu_e \not= \overline {\nu_e}$$

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user11412
user11412
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