Skip to main content

Timeline for Why is D-T fusion easier than T-T?

Current License: CC BY-SA 4.0

9 events
when toggle format what by license comment
S Nov 17, 2023 at 18:11 history suggested Alden Park CC BY-SA 4.0
astrophysical S-factor equation error (it had the wrong units) and also sign error since eta ~ 1/(relative incident velocity), also a typo.
Nov 16, 2023 at 9:33 review Suggested edits
S Nov 17, 2023 at 18:11
S Apr 29, 2017 at 18:18 history suggested Joe D CC BY-SA 3.0
fixed mathematical formatting: exp is typeset upright, and formula for S(E) is now centered/displaystyle
Apr 29, 2017 at 17:59 review Suggested edits
S Apr 29, 2017 at 18:18
Apr 28, 2017 at 20:01 comment added Maury Markowitz Ok I think I get this. This also helps explain other texts I've read about resonances that didn't really explain what they meant. So in this case when the D-T gets close enough together it sort of thinks its a single He5 instead of two separate things, as long as the energy is thus. But in T-T the energy level where they see themselves as a single thing is much higher? And that's possible BECAUSE its unstable and thus has a wide resonance.
Apr 28, 2017 at 19:59 vote accept Maury Markowitz
Apr 28, 2017 at 19:45 comment added jaromrax It happens that it is close enough. The "resonance" - every energy level has some width, it is never "discrete" value unless it lives forever (Heisenberg relations). If the level is already unbound, it is usually quite wide, it could be even MeVs, this one is 74.5 keV. At any small kinetic energy, the particles feel, they are inside. How much they feel at different energies - look at the bump in S-factor picture.
Apr 28, 2017 at 18:55 comment added Maury Markowitz So I'm trying to parse this. It seems the "trick" here is that there is an energy level in He5 that just happens to be lower than in He6? I'm not sure I fully understand resonances in this context.
Apr 28, 2017 at 16:38 history answered jaromrax CC BY-SA 3.0