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Apr 26, 2017 at 4:13 vote accept daniel
Apr 25, 2017 at 4:08 comment added ZeroTheHero It does actually: this is more or less the contents of Robertson's derivation of the uncertainty relation. But your question is implicitly deeper IMO because there is some "classical" uncertainty, which is deeply related to the way detectors are coupled to quantum states, as per Arthurs and Kelly (a nice paper... also Stig Stenholm has nice work on this)
Apr 24, 2017 at 22:23 answer added knzhou timeline score: 1
Apr 24, 2017 at 22:02 answer added tparker timeline score: 2
Apr 24, 2017 at 21:49 history edited daniel CC BY-SA 3.0
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Apr 24, 2017 at 21:39 history edited daniel CC BY-SA 3.0
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Apr 24, 2017 at 21:17 history edited daniel CC BY-SA 3.0
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Apr 24, 2017 at 21:00 history edited daniel CC BY-SA 3.0
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Apr 24, 2017 at 20:50 history edited daniel CC BY-SA 3.0
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Apr 24, 2017 at 20:07 comment added ZeroTheHero @daniel be so kind as to post a reference link please... :) Thanks for the link!
Apr 24, 2017 at 20:05 history edited Qmechanic
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Apr 24, 2017 at 19:53 comment added ZeroTheHero There is more by Uffink and Maassen on the interpretation and difference between the quantum and classical versions (seeEq.(14) in here stanford.library.sydney.edu.au/entries/qt-uncertainty for example of the kinds of delicate discussions involved.)
Apr 24, 2017 at 19:43 comment added ZeroTheHero Part of the delicate nature of the discussion is that the constants are quite important. Crawford ("Waves; Berkeley physics course vol. 3." (1968)) gives $\Delta k\Delta x\ge 2\pi $ from Fourier analysis of a pulse. There is also work by Arthurs and Kelly ("BSTJ briefs: On the simultaneous measurement of a pair of conjugate observables." The Bell System Technical Journal 44.4 (1965): 725-729.) which gives a kind of "classical limit" to the quantum uncertainty relation. See also work by Ozawa v.g. arxiv.org/pdf/quant-ph/0207121.pdf. Getting the constants right is the tricky part.
Apr 24, 2017 at 17:50 history edited Emilio Pisanty CC BY-SA 3.0
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Apr 24, 2017 at 17:49 history edited daniel CC BY-SA 3.0
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Apr 24, 2017 at 17:36 history edited daniel CC BY-SA 3.0
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Apr 24, 2017 at 17:33 history undeleted daniel
Apr 22, 2017 at 20:30 history deleted daniel via Vote
Apr 22, 2017 at 20:20 comment added ACuriousMind I think my answer to the first question I linked answers that - the QM uncertainty relation is a much more general consequence of the non-commutativity of operators.
Apr 22, 2017 at 20:00 comment added ACuriousMind Related/possible duplicates (I'm not quite sure what you're asking): physics.stackexchange.com/q/197821/50583, physics.stackexchange.com/q/47458/50583
Apr 22, 2017 at 19:54 history edited Qmechanic CC BY-SA 3.0
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Apr 22, 2017 at 19:53 history asked daniel CC BY-SA 3.0