Timeline for How do we apply Ampère's law for non-planar loops?
Current License: CC BY-SA 3.0
25 events
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| S Apr 5, 2017 at 13:10 | history | bounty ended | oops | ||
| S Apr 5, 2017 at 13:10 | history | notice removed | oops | ||
| Apr 1, 2017 at 18:54 | history | tweeted | twitter.com/StackPhysics/status/848247215244103681 | ||
| Apr 1, 2017 at 15:43 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
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| Apr 1, 2017 at 14:13 | comment | added | ProfRob | I still don't understand your question and you should edit it to remove the mistakes and clarify. Are you asking how the right hand side (note that at present you refer in your question to the RHS being a line integral of the B-field??) remains the same for any choice of surface (not curve) bounded by the arbitrary loop? | |
| Apr 1, 2017 at 13:38 | history | edited | Emilio Pisanty | CC BY-SA 3.0 |
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| Apr 1, 2017 at 13:37 | answer | added | Emilio Pisanty | timeline score: 1 | |
| Apr 1, 2017 at 11:45 | comment | added | oops | a loop that can be wholly contained by a single plane. or more precisely vector product of any two lengths of the lo0p remains the same(direction wise). | |
| Apr 1, 2017 at 11:42 | comment | added | ProfRob | What is a non-planar loop? | |
| S Apr 1, 2017 at 11:37 | history | bounty started | oops | ||
| S Apr 1, 2017 at 11:37 | history | notice added | oops | Improve details | |
| Mar 31, 2017 at 8:47 | history | edited | oops | CC BY-SA 3.0 |
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| Mar 30, 2017 at 9:33 | comment | added | Photon | I think, you are confusing the loop (which is given by the current density) and the integration curve (which can be choosen arbitrarily). Depending on your choice of the curve, you will get an equation which can be solved for the field B or not. So all choices are possible, but not all are helpful. Usually, your curve will depend on some parameter, which will then become a coordinate, B depends on. I'd advise you to have a look at the derivation of the magnetic field for a planar loop and see how the choice of the integration path enters into the calculation. | |
| Mar 30, 2017 at 9:27 | comment | added | oops | How....?? B field along the loop would remain same in each case, no matter which curve we chose. Besides what can current enclosed by non planar loop possibly mean? | |
| Mar 30, 2017 at 9:25 | comment | added | Photon | If the current enclosed by the curve is different for two curves, then so is the the integral of the magnetic field along them. | |
| Mar 30, 2017 at 9:23 | review | Close votes | |||
| Mar 30, 2017 at 15:47 | |||||
| Mar 30, 2017 at 9:19 | comment | added | oops | But current enclosed would be differnt for each curve. while the line integral remains in each case. | |
| Mar 30, 2017 at 9:17 | comment | added | Photon | An infinite amount of curves can pass through a planar loop as well. Just choose any, which is easy to integrate. | |
| Mar 30, 2017 at 9:13 | history | edited | oops | CC BY-SA 3.0 |
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| Mar 30, 2017 at 9:08 | review | Low quality answers | |||
| Mar 30, 2017 at 9:13 | |||||
| Mar 30, 2017 at 9:02 | comment | added | oops | What would current enclosed mean in case of non planar loops? Infinte amount of curves can pass through such loop | |
| Mar 30, 2017 at 9:00 | comment | added | Photon | Ok, you need the form, where the integral of the current density is not yet done, like the first and second part of this equation: wikimedia.org/api/rest_v1/media/math/render/svg/… | |
| Mar 30, 2017 at 8:58 | comment | added | Photon | Is one of the sides of the equation an integral of the current density or is it just the total current? | |
| Mar 30, 2017 at 8:54 | comment | added | Photon | Could you please state, which form of Ampère's law you are referring to? In the form I know the current is arbitrary, so it doesn't have to be restricted to a loop. | |
| Mar 30, 2017 at 8:51 | history | asked | oops | CC BY-SA 3.0 |