Timeline for Values for angular momentum in energy levels of isotropic Harmonic oscillator
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Feb 1, 2017 at 19:41 | vote | accept | soap | ||
| Jan 27, 2017 at 21:27 | history | edited | soap | CC BY-SA 3.0 |
added 2 characters in body
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| Jan 27, 2017 at 17:44 | comment | added | soap | @EmilioPisanty Please check my edit. | |
| Jan 27, 2017 at 17:43 | history | edited | soap | CC BY-SA 3.0 |
Added a new method
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| Jan 27, 2017 at 16:02 | comment | added | Emilio Pisanty | The point is that the notation is nonstandard, so you need to explicitly say what you mean by $3\mathcal E(·)$. | |
| Jan 27, 2017 at 15:35 | comment | added | soap | @EmilioPisanty No: by $3\mathcal{E}(n=1,l=0)$ I mean the direct sum of three spaces $\mathcal{E}(n=1,l=0)$. $\mathcal{E}(n=1)$ is the eigenspace of $H$ for the eigenvalue (energy) corresponding to $n=1$. Also, $\mathcal{E}(n=1,l=0)=\mathcal{E}(n=1)\otimes \mathcal{E}(l=0)$. | |
| Jan 27, 2017 at 15:22 | vote | accept | soap | ||
| Jan 27, 2017 at 15:22 | |||||
| Jan 27, 2017 at 14:15 | answer | added | ZeroTheHero | timeline score: 2 | |
| Jan 27, 2017 at 13:52 | answer | added | Emilio Pisanty | timeline score: 1 | |
| Jan 27, 2017 at 13:20 | comment | added | Emilio Pisanty | What is $\mathcal E(n=1)$, and why can you multiply it by scalars? If $\mathcal E(n=1)\subset\mathcal H$ is a vector space, do you not mean $\mathrm{dim}(\mathcal E(n=1))$ instead? | |
| Jan 27, 2017 at 12:21 | history | asked | soap | CC BY-SA 3.0 |