Timeline for How is tension the same?
Current License: CC BY-SA 3.0
16 events
| when toggle format | what | by | license | comment | |
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| Mar 6, 2018 at 16:20 | vote | accept | Pablo | ||
| Nov 27, 2016 at 18:52 | comment | added | garyp | The magnitudes of the accelerations are the same, but not the directions. | |
| Nov 27, 2016 at 18:37 | history | reopened | Qmechanic♦ | ||
| Nov 27, 2016 at 18:36 | history | closed |
garyp Qmechanic♦ |
Duplicate of Why I think tension should be twice the force in a tug of war, Stretch length of horizontal and vertical springs | |
| Nov 27, 2016 at 18:34 | history | edited | Qmechanic♦ |
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| Nov 27, 2016 at 18:31 | answer | added | D. Ennis | timeline score: 0 | |
| Nov 27, 2016 at 17:28 | answer | added | Farcher | timeline score: 1 | |
| Nov 27, 2016 at 17:12 | comment | added | Pirx | The cable keeps the two objects at fixed positions relative to each other. Think about what that means. And, no, the two objects accelerate according to the respective net forces acting on them, which includes the force from the rope, not just the weight. | |
| Nov 27, 2016 at 17:08 | comment | added | Pablo | @Pirx I read it but I can't visualize it, how does having the same cable create the same acceleration, when the elevator goes up that allows the other object to go down according to its weight. Same thing for the elevator, it goes down according to its weight doesn't it? | |
| Nov 27, 2016 at 17:02 | comment | added | Pablo | @Pirx but why is the acceleration of the objects the same if they are both pulled by different weights? | |
| Nov 27, 2016 at 17:01 | review | Close votes | |||
| Nov 27, 2016 at 18:40 | |||||
| Nov 27, 2016 at 16:55 | comment | added | Pirx | Not a duplicate since this one involves acceleration in an essential way. @Pablo: The(magnitude of) acceleration of the two objects is obviously the same, since they are connected by the cable. However, the accelerating force (your net force) will be different between the two, since their masses are different. So, in one case that force is $F_{a_E}=m_E\, a$, in the other it's $F_{a_C}=m_C\, a$. Note also that the signs of the forces will be different between the two. | |
| Nov 27, 2016 at 16:47 | comment | added | Pablo | @garyp I get that example because both person A and B are pulling with the same force. However, the two elevators have different weights, pulling with different forces | |
| Nov 27, 2016 at 16:44 | comment | added | garyp | Possible duplicate of Why I think tension should be twice the force in a tug of war | |
| Nov 27, 2016 at 16:35 | history | edited | Pablo | CC BY-SA 3.0 |
added 266 characters in body
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| Nov 27, 2016 at 16:29 | history | asked | Pablo | CC BY-SA 3.0 |