Timeline for Angular velocity: $\omega = vr$ or $\omega = v/r$? [closed]
Current License: CC BY-SA 3.0
30 events
| when toggle format | what | by | license | comment | |
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| Mar 31, 2022 at 10:43 | review | Suggested edits | |||
| Mar 31, 2022 at 13:18 | |||||
| Apr 28, 2021 at 12:12 | review | Suggested edits | |||
| Apr 28, 2021 at 15:17 | |||||
| Nov 28, 2016 at 14:39 | history | closed |
Gert user36790 freecharly Jon Custer AccidentalFourierTransform |
Not suitable for this site | |
| Nov 27, 2016 at 23:00 | history | edited | rob♦ |
edited tags
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| Nov 27, 2016 at 21:29 | comment | added | sammy gerbil | Textbook misprint. | |
| Nov 27, 2016 at 16:19 | vote | accept | Nayeem Nmn | ||
| Nov 27, 2016 at 15:03 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
added 171 characters in body; edited tags; edited title
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| Nov 27, 2016 at 15:02 | review | Close votes | |||
| Nov 28, 2016 at 14:39 | |||||
| S Nov 27, 2016 at 15:01 | history | post merged (destination) | |||
| Nov 27, 2016 at 15:00 | history | undeleted | Qmechanic♦ | ||
| Nov 27, 2016 at 14:53 | comment | added | Nayeem Nmn | @Emilio Pisanty yes! Got it! | |
| Nov 27, 2016 at 14:47 | comment | added | Emilio Pisanty | Your first image is wrong - the identification of $vr$ as an angular velocity is plain wrong. Find a better textbook. (On the other hand, the formula $mvr=nh/2\pi$ isn't wrong - you just need to set the angular momentum $L=mvr$ as equal to $m\omega r^2$.) | |
| Nov 27, 2016 at 14:41 | history | deleted | Nayeem Nmn | via Vote | |
| Nov 27, 2016 at 14:40 | comment | added | Nayeem Nmn | @Qmchanic sorry about that! New here! | |
| Nov 27, 2016 at 14:40 | vote | accept | Nayeem Nmn | ||
| S Nov 27, 2016 at 15:01 | |||||
| Nov 27, 2016 at 14:37 | review | Close votes | |||
| Nov 27, 2016 at 14:42 | |||||
| Nov 27, 2016 at 14:35 | comment | added | Qmechanic♦ | Hi Nayeem Nmn. Please don't repost a question in a new entry. Instead, you are supposed to edit the original question within the original entry. | |
| Nov 27, 2016 at 14:34 | comment | added | Floris | It is used for angular momentum which is not $m\omega$... | |
| Nov 27, 2016 at 14:33 | comment | added | Nayeem Nmn | Dimension analysis tell me it should be w=v/r! But tge formular mvr= n*h/2*pi is extensive ly used! Can it be wrong?!! | |
| Nov 27, 2016 at 14:33 | history | undeleted | Qmechanic♦ | ||
| Nov 27, 2016 at 14:29 | answer | added | Floris | timeline score: 3 | |
| Nov 27, 2016 at 14:27 | answer | added | Steeven | timeline score: 1 | |
| Nov 27, 2016 at 14:26 | comment | added | Floris | What does dimensional analysis tell you? | |
| Nov 27, 2016 at 14:21 | history | deleted | Nayeem Nmn | via Vote | |
| Nov 27, 2016 at 14:12 | comment | added | Farcher | $\vec \omega=\frac{\vec r \times\vec v}{|\vec r|^2}$ | |
| Nov 27, 2016 at 13:51 | review | Close votes | |||
| S Nov 27, 2016 at 14:22 | |||||
| Nov 27, 2016 at 13:33 | comment | added | Gert | I'm voting to close this question as off-topic because it shows no research effort. | |
| Nov 27, 2016 at 13:32 | comment | added | Gert | $\omega$ is angular velocity (in $\mathrm{s^{-1}}$), $v$ is speed (in $\mathrm{ms^{-1}}$). $v=\omega R$: just look at the units. | |
| Nov 27, 2016 at 13:14 | review | First posts | |||
| S Nov 27, 2016 at 14:22 | |||||
| Nov 27, 2016 at 13:14 | history | asked | Nayeem Nmn | CC BY-SA 3.0 |