Timeline for Why are only some portions of the EM spectrum able to pass through a metal dog bowl?
Current License: CC BY-SA 3.0
20 events
when toggle format | what | by | license | comment | |
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S Dec 14, 2016 at 1:41 | history | bounty ended | CommunityBot | ||
S Dec 14, 2016 at 1:41 | history | notice removed | CommunityBot | ||
Dec 13, 2016 at 4:33 | vote | accept | Lambda | ||
Dec 11, 2016 at 19:16 | comment | added | akhmeteli | @RobJeffries: I did not ascribe to you something that you did not write. I just had an impression that you doubted the OP's "experimental results", and the OP insisted on the results. So I was trying to say that there is no direct contradiction between your statement and the OP's results. | |
Dec 11, 2016 at 18:58 | comment | added | ProfRob | @CoilKid I know what a cache is. I pointed out the flaw in this particular experiment in my comments above. | |
S Dec 11, 2016 at 18:01 | history | suggested | CoilKid | CC BY-SA 3.0 |
Fixed grammer, improved clarity, and changed title. (Some subjectivity was required.)
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Dec 11, 2016 at 17:29 | comment | added | CoilKid | @RobJefferies, The music still plays without issues because your phone saves the song to a cache. That way, it can avoid network lag by always being a few songs ahead of the one you're listening to. (At least for streaming music.) | |
Dec 11, 2016 at 17:26 | comment | added | CoilKid | @RobJeffries is correct that it will not pass through the metal. Probably what is happening is that you were not creating a perfect Faraday cage. (If you place a phone on a counter and place a metal bowl over that, it won't stop the EM waves. That's because while the metal dog bowl can stop the waves, the counter can't. Basically, you just create a shielded hemisphere, which would defeat the purpose of the experiment. Remember: EM waves can also be reflected around. Your experiment has to account for that.) | |
Dec 11, 2016 at 17:17 | review | Suggested edits | |||
S Dec 11, 2016 at 18:01 | |||||
Dec 11, 2016 at 11:41 | comment | added | G. Bergeron | it passes under the bowl... You have to realize the extreme optimization of the channel capacity that is engineered into modern cellphones. They do a lot even in unfavourable conditions. | |
Dec 9, 2016 at 16:28 | comment | added | akhmeteli | @RobJeffries: My impression is, in the OP's question, long-wavelength radiation does not pass "through" the bowl, but it could pass around it, due to diffraction. | |
Dec 6, 2016 at 18:59 | comment | added | ProfRob | I just tried your streaming experiment. The problem is that I find a song will play all the way through, even if I turn the wifi off. Just tried again in my office with a phone call, and the foil blocks it fine. | |
Dec 6, 2016 at 18:26 | comment | added | ProfRob | I did the demo this morning in my lecture - the same one I do every year. A mobile phone does not work (will not receive phone calls) when wrapped in aluminium foil. Ditto a radio wrapped in a single sheet of aluminium foil. Do the Math. | |
Dec 6, 2016 at 17:43 | comment | added | Lambda | Stream music or any other sound onto your phone from a wifi network. Wrap the phone in aluminum foil, one layer, and it will still work well beyond buffering time. | |
Dec 6, 2016 at 15:53 | comment | added | Lambda | It does. The cell phone works under the metal bowl. Try it. | |
Dec 6, 2016 at 14:47 | comment | added | ProfRob | Radio waves and microwaves will NOT pass "through a dog bowl", if it is made, as it appears, from aluminium or any other conductive material. | |
Dec 6, 2016 at 1:36 | answer | added | akhmeteli | timeline score: 2 | |
S Dec 6, 2016 at 0:37 | history | bounty started | Lambda | ||
S Dec 6, 2016 at 0:37 | history | notice added | Lambda | Draw attention | |
Nov 17, 2016 at 1:53 | history | asked | Lambda | CC BY-SA 3.0 |