Timeline for Getting from $E^2 - p^2c^2 = m^2c^4$ to $E = \gamma mc^2$ [closed]
Current License: CC BY-SA 3.0
18 events
| when toggle format | what | by | license | comment | |
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| Nov 10, 2013 at 16:08 | history | closed |
tpg2114 akhmeteli Emilio Pisanty user10851 Qmechanic♦ |
Not suitable for this site | |
| Nov 8, 2013 at 17:28 | review | Close votes | |||
| Nov 10, 2013 at 16:08 | |||||
| May 20, 2012 at 10:53 | comment | added | ODP | As the $m$ here is for a body in movement, should it be $m_\text{rel}$ | |
| May 20, 2012 at 10:52 | comment | added | ODP | Who's to say it would be basic? | |
| May 20, 2012 at 2:52 | comment | added | David Z | By the way, while you're allowed to ask for it, the level of mathematical detail you seem to want is more than an answers on this site are expected to give. In other words, it's really not our job to explain basic algebra. | |
| May 20, 2012 at 2:45 | comment | added | David Z | There's nothing wrong with using $m$ for rest mass, as that is the modern convention. | |
| May 18, 2012 at 18:57 | answer | added | Ron Maimon | timeline score: 3 | |
| May 18, 2012 at 16:49 | vote | accept | ODP | ||
| May 18, 2012 at 16:19 | answer | added | kηives | timeline score: 12 | |
| May 18, 2012 at 16:08 | answer | added | qoqosz | timeline score: 2 | |
| May 18, 2012 at 16:08 | history | edited | ODP | CC BY-SA 3.0 |
added 36 characters in body
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| May 18, 2012 at 15:58 | comment | added | ODP | @JohnRennie I have reverted your edit, but please do correct me if I'm wrong | |
| May 18, 2012 at 15:57 | history | edited | ODP | CC BY-SA 3.0 |
deleted 2 characters in body
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| May 18, 2012 at 15:53 | comment | added | ODP | Oh wait, I think this is for when it's moving, because this equation $E=\gamma mc^2$ goes to show how if an object reached the speed of light it would have used infinite energy (although it's not strictly true) and as far as I know $E^2 - p^2c^2 = m^2c^4$ is for objects that are moving, so surely $E=\gamma mc^2$ would be for a moving object? | |
| May 18, 2012 at 15:46 | comment | added | John Rennie | I've changed $m$ to $m_0$ to make it clear it's the rest mass. If you didn't mean this please revert my edit. | |
| May 18, 2012 at 15:46 | history | edited | John Rennie | CC BY-SA 3.0 |
added 4 characters in body
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| May 18, 2012 at 15:35 | history | edited | Qmechanic♦ |
The math phys tag does not apply.
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| May 18, 2012 at 15:23 | history | asked | ODP | CC BY-SA 3.0 |