Timeline for Why is the the differential of Helmoltz free energy dT dependent?
Current License: CC BY-SA 3.0
6 events
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Sep 24, 2016 at 15:09 | comment | added | StarBucK | Yeah what I meant is to define F=U-TS we putted dT=0 in dU+PdV-TdS to find F=U-TS But indeed we can make T dependent it is just that if F is T dependent then the condition F=Fmin at equilibrium will not be true. Thank you | |
Sep 24, 2016 at 14:00 | comment | added | Dominic Else | We didn't assume dT=0 to "construct" F. We just defined F = U - TS. This definition certainly does not require fixed temperature. Now, it's true that the statement $dF \leq 0$ is true for systems coupled to a thermal bath of fixed temperature, but that doesn't mean that we can't still talk about the temperature dependence of $F$. | |
Sep 23, 2016 at 11:20 | comment | added | StarBucK | Nobody has an idea (I don't know how to up a post) ? | |
Sep 22, 2016 at 17:59 | history | edited | StarBucK | CC BY-SA 3.0 |
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Sep 22, 2016 at 17:47 | answer | added | Riccardo Petraglia | timeline score: 0 | |
Sep 22, 2016 at 17:33 | history | asked | StarBucK | CC BY-SA 3.0 |