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Bohr / De Broglie postulate (what does n$n λ= 2 π rr$ imply)

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Bohr / De Broglie postulate (what does n c /f=λ= 2 π r imply)

From the Bohr/De Broglie postulate we have n c/fλ = 2πr where fλ is the De-Broglie frequencywavelength , r is the radius corresponding to n and n is the quantum number.

  1. An electron in the state n=2 has more energy than that at n=1
  2. That implies that the De- Broglie frequency associatedwavelength associated with the electron should also increasedecrease ?

From the postulate..it is the other way i.e. the frequency decreaseswavelength increases as the electron gains energy. How is this possible?.( I had assumed that frequency increaseswavelength decreases with energy)

if we calculate the De-Broglie frequencies fromwavelengths from the postulate:

for n=1 ; fλ = 9*10^19 Hz33 * 10^-11 m

for n=2 ; fλ = 4.566 * 10^19 Hz10^-11 m

does this mean that as the energy of the electron increases the corresponding De-Broglie frequency decreaseswavelength increases?! may be i am missing something very basic here.

Bohr / De Broglie postulate (what does n c /f= 2 π r imply)

From the Bohr/De Broglie postulate we have n c/f = 2πr where f is the De-Broglie frequency, r is the radius corresponding to n and n is the quantum number.

  1. An electron in the state n=2 has more energy than that at n=1
  2. That implies that the De- Broglie frequency associated with the electron should also increase ?

From the postulate..it is the other way i.e. the frequency decreases as the electron gains energy. How is this possible( I had assumed that frequency increases with energy)

if we calculate the De-Broglie frequencies from the postulate:

for n=1 ; f = 9*10^19 Hz

for n=2 ; f = 4.5 * 10^19 Hz

does this mean that as the energy of the electron increases the corresponding De-Broglie frequency decreases?! may be i am missing something very basic here.

Bohr / De Broglie postulate (what does n λ= 2 π r imply)

From the Bohr/De Broglie postulate we have n λ = 2πr where λ is the De-Broglie wavelength , r is the radius corresponding to n and n is the quantum number.

  1. An electron in the state n=2 has more energy than that at n=1
  2. That implies that the De- Broglie wavelength associated with the electron should also decrease ?

From the postulate..it is the other way i.e. the wavelength increases as the electron gains energy. How is this possible?.( I had assumed that wavelength decreases with energy)

if we calculate the De-Broglie wavelengths from the postulate:

for n=1 ; λ = 33 * 10^-11 m

for n=2 ; λ = 66 * 10^-11 m

does this mean that as the energy of the electron increases the corresponding De-Broglie wavelength increases?! may be i am missing something very basic here.

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Bohr / De Broglie postulate (what does n c /f= 2 π r imply)

From the Bohr/De Broglie postulate we have n c/f = 2πr where f is the De-Broglie frequency, r is the radius corresponding to n and n is the quantum number.

  1. An electron in the state n=2 has more energy than that at n=1
  2. That implies that the De- Broglie frequency associated with the electron should also increase ?

From the postulate..it is the other way i.e. the frequency decreases as the electron gains energy. How is this possible( I had assumed that frequency increases with energy)

if we calculate the De-Broglie frequencies from the postulate:

for n=1 ; f = 9*10^19 Hz

for n=2 ; f = 4.5 * 10^19 Hz

does this mean that as the energy of the electron increases the corresponding De-Broglie frequency decreases?! may be i am missing something very basic here.