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The static pressure $p$ depends solely on the height $h$. If $p_0$ is the atmospheric pressure, then:

$$p=p_0+\rho gh$$

Where $\rho$ is the liquid's density and $g\approx10\:\mathrm{ms^{-2}}$.

So for the left hand side tank the pressure would be slightly higher because the tank is taller (not because it has higher or lower capacity).

Flow through the pipe always causes some viscous pressure loss though.

Answering OP's concern (comment section):

Do I need a tank and secondly as far as I can gather from you guys it is the pressure that the water leaves the bottom of the tank is the pressure at the end of the pipe?

If you have easy access to the stream, a tank is not required.

The pressure discussed in my answer is called hydrostatic pressure and for good reason: if one blocks the end of the pipe, the pressure $p$ at that point would be exactly as indicated ($p=p_0+\rho gh$, where $h$ is the height difference between the water's open surface and the pipe's end).

But when flow is allowed a certain amount of pressure is lost due to friction in the pipe. In that case the corrected pressure can be noted as:

$$p'=p_0+\rho gh-\Delta p$$ Without going into full details of pipe flow theory we can say with certainty that $\Delta p$:

1. increases with pipe length,
2. decreases with pipe diameter,
3. increases with volumetric throughput (flow speed),
4. increases with pipe inside roughness: smooth, uncorroded, new pipes reduce pressure less,
5. increases in the presence of local resistances like bends, kinks, valves, sudden diameter changes and such like.

A short, wide, smooth, straight pipe operated at low flow speed will deliver pressure almost identical to the hydrostatic pressure $p$.

But using a long, narrow (etc) pipe can lead to almost all of the hydrostatic pressure being lost to friction ($\Delta p \approx p_0+\rho gh$).

Further reading: Darcy-Weisbach.

The static pressure $p$ depends solely on the height $h$. If $p_0$ is the atmospheric pressure, then:

$$p=p_0+\rho gh$$

Where $\rho$ is the liquid's density and $g\approx10\:\mathrm{ms^{-2}}$.

So for the left hand side tank the pressure would be slightly higher because the tank is taller (not because it has higher or lower capacity).

Flow through the pipe always causes some viscous pressure loss though.

Answering OP's concern (comment section):

Do I need a tank and secondly as far as I can gather from you guys it is the pressure that the water leaves the bottom of the tank is the pressure at the end of the pipe?

If you have easy access to the stream, a tank is not required.

The pressure discussed in my answer is called hydrostatic pressure and for good reason: if one blocks the end of the pipe, the pressure $p$ at that point would be exactly as indicated above ($p=p_0+\rho gh$, where $h$ is the height difference between the water's open surface and the pipe's end).

But when flow is allowed a certain amount of pressure is lost due to friction in the pipe. In that case the corrected pressure can be noted as:

$$p'=p_0+\rho gh-\Delta p$$ Without going into full details of pipe flow theory we can say with certainty that $\Delta p$:

1. increases with pipe length,
2. decreases with pipe diameter,
3. increases with volumetric throughput (flow speed),
4. increases with pipe inside roughness: smooth, uncorroded, new pipes reduce pressure less,
5. increases in the presence of local resistances like bends, kinks, valves, sudden diameter changes and such like.

A short, wide, smooth, straight pipe operated at low flow speed will deliver pressure almost identical to the hydrostatic pressure $p$.

But using a long, narrow (etc) pipe can lead to almost all of the hydrostatic pressure being lost to friction ($\Delta p \approx p_0+\rho gh$).

Further reading: Darcy-Weisbach.

The static pressure $p$ depends solely on the height $h$. If $p_0$ is the atmospheric pressure, then:

$$p=p_0+\rho gh$$

Where $\rho$ is the liquid's density and $g\approx10\:\mathrm{ms^{-2}}$.

So for the left hand side tank the pressure would be slightly higher because the tank is taller (not because it has higher or lower capacity).

Flow through the pipe always causes some viscous pressure loss though.

Answering OP's concern (comment section):

Do I need a tank and secondly as far as I can gather from you guys it is the pressure that the water leaves the bottom of the tank is the pressure at the end of the pipe?

The pressure discussed in my answer is called hydrostatic pressure and for good reason: if one blocks the end of the pipe, the pressure $p$ at that point would be exactly as indicated ($p=p_0+\rho gh$, where $h$ is the height difference between the water's open surface and the pipe's end).

But when flow is allowed a certain amount of pressure is lost due to friction in the pipe. In that case the corrected pressure can be noted as:

$$p'=p_0+\rho gh-\Delta p$$ Without going into full details of pipe flow theory we can say with certainty that $\Delta p$:

1. increases with pipe length,
2. decreases with pipe diameter,
3. increases with volumetric throughput (flow speed),
4. increases with pipe inside roughness: smooth, uncorroded, new pipes reduce pressure less,
5. increases in the presence of local resistances like bends, kinks, valves, sudden diameter changes and such like.

A short, wide, smooth, straight pipe operated at low flow speed will deliver pressure almost identical to the hydrostatic pressure $p$.

But using a long, narrow (etc) pipe can lead to almost all of the hydrostatic pressure being lost to friction ($\Delta p \approx p_0+\rho gh$).

Further reading: Darcy-Weisbach.

The static pressure $p$ depends solely on the height $h$. If $p_0$ is the atmospheric pressure, then:

$$p=p_0+\rho gh$$

Where $\rho$ is the liquid's density and $g\approx10\:\mathrm{ms^{-2}}$.

So for the left hand side tank the pressure would be slightly higher because the tank is taller (not because it has higher or lower capacity).

Flow through the pipe always causes some viscous pressure loss though.

Answering OP's concern (comment section):

Do I need a tank and secondly as far as I can gather from you guys it is the pressure that the water leaves the bottom of the tank is the pressure at the end of the pipe?

If you have easy access to the stream, a tank is not required.

The pressure discussed in my answer is called hydrostatic pressure and for good reason: if one blocks the end of the pipe, the pressure $p$ at that point would be exactly as indicated ($p=p_0+\rho gh$, where $h$ is the height difference between the water's open surface and the pipe's end).

But when flow is allowed a certain amount of pressure is lost due to friction in the pipe. In that case the corrected pressure can be noted as:

$$p'=p_0+\rho gh-\Delta p$$ Without going into full details of pipe flow theory we can say with certainty that $\Delta p$:

1. increases with pipe length,
2. decreases with pipe diameter,
3. increases with volumetric throughput (flow speed),
4. increases with pipe inside roughness: smooth, uncorroded, new pipes reduce pressure less,
5. increases in the presence of local resistances like bends, kinks, valves, sudden diameter changes and such like.

A short, wide, smooth, straight pipe operated at low flow speed will deliver pressure almost identical to the hydrostatic pressure $p$.

But using a long, narrow (etc) pipe can lead to almost all of the hydrostatic pressure being lost to friction ($\Delta p \approx p_0+\rho gh$).

Further reading: Darcy-Weisbach.

The static pressure $p$ depends solely on the height $h$. If $p_0$ is the atmospheric pressure, then:

$$p=p_0+\rho gh$$

Where $\rho$ is the liquid's density and $g\approx10\:\mathrm{ms^{-2}}$.

So for the left hand side tank the pressure would be slightly higher because the tank is taller (not because it has higher or lower capacity).

Flow through the pipe always causes some viscous pressure loss though.

The static pressure $p$ depends solely on the height $h$. If $p_0$ is the atmospheric pressure, then:

$$p=p_0+\rho gh$$

Where $\rho$ is the liquid's density and $g\approx10\:\mathrm{ms^{-2}}$.

So for the left hand side tank the pressure would be slightly higher because the tank is taller (not because it has higher or lower capacity).

Flow through the pipe always causes some viscous pressure loss though.

Answering OP's concern (comment section):

Do I need a tank and secondly as far as I can gather from you guys it is the pressure that the water leaves the bottom of the tank is the pressure at the end of the pipe?

The pressure discussed in my answer is called hydrostatic pressure and for good reason: if one blocks the end of the pipe, the pressure $p$ at that point would be exactly as indicated ($p=p_0+\rho gh$, where $h$ is the height difference between the water's open surface and the pipe's end).

But when flow is allowed a certain amount of pressure is lost due to friction in the pipe. In that case the corrected pressure can be noted as:

$$p'=p_0+\rho gh-\Delta p$$ Without going into full details of pipe flow theory we can say with certainty that $\Delta p$:

1. increases with pipe length,
2. decreases with pipe diameter,
3. increases with volumetric throughput (flow speed),
4. increases with pipe inside roughness: smooth, uncorroded, new pipes reduce pressure less,
5. increases in the presence of local resistances like bends, kinks, valves, sudden diameter changes and such like.

A short, wide, smooth, straight pipe operated at low flow speed will deliver pressure almost identical to the hydrostatic pressure $p$.

But using a long, narrow (etc) pipe can lead to almost all of the hydrostatic pressure being lost to friction ($\Delta p \approx p_0+\rho gh$).

Further reading: Darcy-Weisbach.