[![Pressures.][1]][1]

The *static* pressure $p$ depends solely on the height $h$. If $p_0$ is the atmospheric pressure, then:

$$p=p_0+\rho gh$$

Where $\rho$ is the liquid's density and $g\approx10\:\mathrm{ms^{-2}}$.

So for the left hand side tank the pressure would be slightly higher because the tank is taller (not because it has higher or lower capacity).

Flow through the pipe always causes some viscous pressure loss though.


  [1]: https://i.sstatic.net/A6Nar.png