Timeline for Can I swap quantum mechanical ground state for some classical trajectory distribution and have it sit still after the swap?
Current License: CC BY-SA 3.0
22 events
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| Mar 24, 2017 at 0:25 | answer | added | Cosmas Zachos | timeline score: 0 | |
| S Sep 2, 2016 at 11:41 | history | bounty ended | CommunityBot | ||
| S Sep 2, 2016 at 11:41 | history | notice removed | CommunityBot | ||
| Sep 1, 2016 at 14:05 | answer | added | Void | timeline score: 3 | |
| Sep 1, 2016 at 12:12 | history | edited | Qmechanic♦ |
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| Aug 31, 2016 at 22:05 | answer | added | CR Drost | timeline score: 1 | |
| Aug 31, 2016 at 20:37 | answer | added | Qmechanic♦ | timeline score: 3 | |
| Aug 31, 2016 at 18:29 | comment | added | Qmechanic♦ | Comment to the post (v1): By the word probability distribution, do you mean quasi-probability distribution? | |
| Aug 29, 2016 at 23:58 | answer | added | lytex | timeline score: 2 | |
| S Aug 25, 2016 at 10:27 | history | bounty started | Emilio Pisanty | ||
| S Aug 25, 2016 at 10:27 | history | notice added | Emilio Pisanty | Draw attention | |
| Aug 25, 2016 at 10:26 | history | edited | Emilio Pisanty | CC BY-SA 3.0 |
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| Aug 23, 2016 at 23:09 | comment | added | Emilio Pisanty | @Bob I should think it is obvious that the dynamics of the classical system should correspond to the original quantum system (i.e. the classical system is the classical limit of the quantum system, or the quantum system arises from the classical hamiltonian via (some form of) canonical quantization). What you're saying is essentially a purposeful non-reading of the question. | |
| Aug 23, 2016 at 22:20 | comment | added | La buba | The identity Hamiltonian, whose corresponding evolution can be obviously cast classically. In this case any state is stationary, including the eigenstates of your Hamiltonian. Right ? | |
| Aug 23, 2016 at 17:03 | comment | added | Emilio Pisanty | @Bob What exactly do you mean by the identity? | |
| Aug 23, 2016 at 16:58 | comment | added | La buba | Maybe you should give more constraints, otherwise the identity (which have a trivial classical description) does the job. Am I wrong? | |
| Aug 20, 2016 at 21:12 | comment | added | udrv | A couple of ideas: 1) Based on arxiv.org/abs/0810.2394, see Eq.(10) therein, start as usual with a polar decomposition $\psi=\sqrt{\rho}e^{iS/\hbar}$, identify ${\bf p}\sim\nabla S$, and define a "phase-space probability distribution" as $\rho({\bf x}, t)\delta({\bf p}-\nabla S)$. Then set up the Lagrangian, Hamiltonian etc as discussed at length in paper. 2) Sec.IV.2 in arxiv.org/abs/0712.1984 gives another way to equiv. Hamilton-Jacobi setup, maybe it's worth a look. Once H-J eqs. are in place, translating to/from Schroedinger should be straightforward. | |
| Aug 17, 2016 at 19:47 | history | tweeted | twitter.com/StackPhysics/status/765998555563720705 | ||
| Aug 17, 2016 at 16:20 | comment | added | Bill Alsept | It's not a theory it's a simulator and I was just trying to help. I said I might be off the mark. It sounded like you wanted to derive a particle or classical trajectory solution. | |
| Aug 17, 2016 at 16:01 | comment | added | Emilio Pisanty | Sorry, Bill, but I don't see any relevance at all of your personal theories to this question, and I don't think this is the appropriate place to advertise them. | |
| Aug 17, 2016 at 15:53 | comment | added | Bill Alsept | I'm sure I am way off the mark here but I designed a program to simulate 2D snap shots of slit fringe patterns based on classical trajectories. You can find some of my simulators at billalsept.com | |
| Aug 17, 2016 at 14:33 | history | asked | Emilio Pisanty | CC BY-SA 3.0 |