Timeline for What happens to the electric field at the boundary of a dielectric?
Current License: CC BY-SA 3.0
16 events
when toggle format | what | by | license | comment | |
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S May 12, 2016 at 3:28 | history | bounty ended | FreezingFire | ||
S May 12, 2016 at 3:28 | history | notice removed | FreezingFire | ||
May 12, 2016 at 3:24 | vote | accept | FreezingFire | ||
May 10, 2016 at 5:18 | answer | added | Farcher | timeline score: 4 | |
May 10, 2016 at 4:09 | history | tweeted | twitter.com/StackPhysics/status/729885991952093184 | ||
S May 10, 2016 at 4:07 | history | bounty started | FreezingFire | ||
S May 10, 2016 at 4:07 | history | notice added | FreezingFire | Improve details | |
Apr 28, 2016 at 20:50 | answer | added | user97261 | timeline score: 2 | |
Apr 28, 2016 at 5:36 | history | edited | FreezingFire | CC BY-SA 3.0 |
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Apr 28, 2016 at 3:23 | history | edited | FreezingFire | CC BY-SA 3.0 |
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Apr 27, 2016 at 16:27 | comment | added | Anubhav Goel | I want to know it too. Might be some fringing effect. | |
Apr 27, 2016 at 15:30 | history | edited | FreezingFire | CC BY-SA 3.0 |
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Apr 27, 2016 at 15:29 | comment | added | FreezingFire | @AnubhavGoel Yes, $V_A-V_B$ works, but i want to know why the field method doesn't work here! I am speculating that something wierd happens to the field at the dielectric boundary, and i want to know what that is! Oh, and i meant the potential difference across k1 and k2 were as written. I will correct it immediately! | |
Apr 27, 2016 at 11:32 | comment | added | Anubhav Goel | Why are you calculating E.dr ? Won't Va - Vb work? | |
Apr 27, 2016 at 11:29 | comment | added | Anubhav Goel | Isn't $V_B = \dfrac{V}{1+\frac xy}$ and similarly $V_A = \dfrac{V}{1+\frac{k_2}{k_1}\frac xy}$$ | |
Apr 27, 2016 at 9:54 | history | asked | FreezingFire | CC BY-SA 3.0 |