Timeline for Are electric field lines always conserved?
Current License: CC BY-SA 3.0
23 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 3, 2016 at 2:43 | history | edited | Anubhav Goel | CC BY-SA 3.0 |
deleted 95 characters in body
|
| Apr 2, 2016 at 15:48 | comment | added | Anubhav Goel | @Shodai No, closed loops are possible. There are even more cases. Have you read about how changing magnetic field produce Electric field? In a particular case , when you increase strength of a uniform magnetic field, you will get closed loops of electric field., whose strength depends on radius of loop. | |
| Apr 1, 2016 at 15:20 | comment | added | Shodai | But aren't closed loops of electric field not possible? | |
| Apr 1, 2016 at 12:45 | comment | added | Anubhav Goel | en.m.wikipedia.org/wiki/Stress_energy_tensor It says SET is source but not in sense you want. | |
| Apr 1, 2016 at 12:40 | comment | added | Anubhav Goel | I think for 1) This is still under huge research. No, clear answer exist. Actually, Electric field is not different but Gravitational field is peculiar , in sense it has no source. | |
| Apr 1, 2016 at 12:35 | comment | added | Anubhav Goel | @Shodai Electric field form closed loops in photons or electromagnetic wave. Just visualize it, as em wave has no charge but has E and M field. | |
| Mar 31, 2016 at 4:30 | comment | added | Shodai | Please see this link - en.wikipedia.org/wiki/Field_line, see the paragraph starting with "As a result of the divergence theorem, field lines start at sources and end at sinks of the vector field." 1.Why is electric field different from gravitational field? 2.In which cases can the fields form closed loops? | |
| Mar 31, 2016 at 4:20 | vote | accept | Shodai | ||
| Mar 31, 2016 at 4:27 | |||||
| Mar 31, 2016 at 4:20 | vote | accept | Shodai | ||
| Mar 31, 2016 at 4:20 | |||||
| Mar 28, 2016 at 15:57 | history | edited | Anubhav Goel | CC BY-SA 3.0 |
added 112 characters in body
|
| Mar 28, 2016 at 15:56 | history | rollback | Anubhav Goel |
Rollback to Revision 3
|
|
| Mar 28, 2016 at 15:53 | history | edited | Anubhav Goel | CC BY-SA 3.0 |
added 94 characters in body
|
| Mar 28, 2016 at 15:48 | history | rollback | Anubhav Goel |
Rollback to Revision 4
|
|
| Mar 28, 2016 at 15:15 | comment | added | Timaeus | You are allowed to have multiple answers. So you could revert this one back to the version that got lots of votes and add a post script (or a header section) saying you now think it is wrong. Then you can keep all the points and don't have existing votes get applied to an essentially new answer. Plus you aren't misleading anyone if you have the post script, it tells people that a lot of other people liked that answer but you don't. And then you can still write a second answer if you want to try to give a complete and correct answer. | |
| Mar 28, 2016 at 14:19 | comment | added | Timaeus | Then there is also one going left towards the zero and coming from infinity. But you can't have two field lines, both going in to the zero point, and both terminating in the vacuum, not without some coming out as well. So field lines must come out of the zero as well, if you have some come in. And they terminate on the negative charge, which is relevant to the OP. In 2d you can have 2 go in and 2 go out, but in 3d you still only have two go in but a many could come out (but can only draw two). You didn't actually draw the zero point, it's not even on your picture. | |
| Mar 28, 2016 at 14:12 | comment | added | Timaeus | Hard to tell in a 2d drawing. You can talk about the field lines in general. But it's usually impossible to draw a consistent version with a finite number of field lines (where each one represents a certain amount of flux) and also have one of the finite number be one of the ones that terminates at the zero of the field. Further, you haven't actually addressed the original question. You correctly point out field like a come from infinity and hit the negative charge. But what about field lines coming out of the zero point? If you draw the field line going right and towards the zero | |
| Mar 28, 2016 at 7:51 | comment | added | Anubhav Goel | @Timaeus Is it okay now? | |
| Mar 28, 2016 at 7:49 | history | edited | Anubhav Goel | CC BY-SA 3.0 |
added 179 characters in body
|
| Mar 28, 2016 at 7:43 | history | edited | Anubhav Goel | CC BY-SA 3.0 |
added 27 characters in body
|
| Mar 23, 2016 at 22:05 | comment | added | Timaeus | The blue lines on the right are not correct. There is no way that lower line can point upwards on the right. The field along the line joining the two charges points along the line, but you don't want to draw that field line because there is a zero field to the right and that field line would terminate there in empty space. But that's the field line that makes it farthest out, the rest turn back before there. For every five lines coming from infinity there is one that starts at the positive charge and terminates on the large negative charge. | |
| Mar 23, 2016 at 4:58 | history | edited | Anubhav Goel | CC BY-SA 3.0 |
deleted 91 characters in body
|
| Mar 23, 2016 at 4:23 | history | edited | Anubhav Goel | CC BY-SA 3.0 |
added 144 characters in body; added 1 character in body; added 2 characters in body
|
| Mar 23, 2016 at 4:17 | history | answered | Anubhav Goel | CC BY-SA 3.0 |