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OP's ket first equation$^1$

$$\tag{1} \hat{p}|x\rangle ~=~+i\hbar\frac{\partial |x\rangle}{\partial x}$$

is explained in eq. (7) of my Phys.SE answer herehere. In short, eq. (1) is consistent with the corresponding bra equation

$$\langle x |\hat{p} ~=~-i\hbar \frac{\partial \langle x |}{\partial x} $$

via Hermitian conjugation. The bra equation in turn is related to OP's second equation

$$ \tag{2}\hat{p} ~=~ -i\hbar \frac{\partial }{\partial x} $$

via the standard convention

$$\psi(x)~=~\langle x | \psi \rangle$$

for the wave function.

--

$^1$ Both sides of the ket equation (1) are kets in an appropriate infinite-dimensional vector space. (Warning: not a Hilbert space, cf. e.g. thisthis Phys.SE post and links therein.). One can multiply eq. (1) from left with a bra $\langle \psi |$ [belonging to an appropriate (possibly different) infinite-dimensional vector space] to achieve an equation

$$\hat{p}\psi(x)^{\ast} ~=~\langle \psi |\hat{p}|x\rangle ~\stackrel{(1)}{=}~+i\hbar\langle \psi |\frac{\partial }{\partial x}|x\rangle ~=~+i\hbar\frac{\partial \langle \psi |x\rangle}{\partial x}~=~+i\hbar\frac{\partial \psi(x)^{\ast}}{\partial x},$$

where both sides are complex numbers.

OP's ket first equation$^1$

$$\tag{1} \hat{p}|x\rangle ~=~+i\hbar\frac{\partial |x\rangle}{\partial x}$$

is explained in eq. (7) of my Phys.SE answer here. In short, eq. (1) is consistent with the corresponding bra equation

$$\langle x |\hat{p} ~=~-i\hbar \frac{\partial \langle x |}{\partial x} $$

via Hermitian conjugation. The bra equation in turn is related to OP's second equation

$$ \tag{2}\hat{p} ~=~ -i\hbar \frac{\partial }{\partial x} $$

via the standard convention

$$\psi(x)~=~\langle x | \psi \rangle$$

for the wave function.

--

$^1$ Both sides of the ket equation (1) are kets in an appropriate infinite-dimensional vector space. (Warning: not a Hilbert space, cf. e.g. this Phys.SE post and links therein.). One can multiply eq. (1) from left with a bra $\langle \psi |$ [belonging to an appropriate (possibly different) infinite-dimensional vector space] to achieve an equation

$$\hat{p}\psi(x)^{\ast} ~=~\langle \psi |\hat{p}|x\rangle ~\stackrel{(1)}{=}~+i\hbar\langle \psi |\frac{\partial }{\partial x}|x\rangle ~=~+i\hbar\frac{\partial \langle \psi |x\rangle}{\partial x}~=~+i\hbar\frac{\partial \psi(x)^{\ast}}{\partial x},$$

where both sides are complex numbers.

OP's ket first equation$^1$

$$\tag{1} \hat{p}|x\rangle ~=~+i\hbar\frac{\partial |x\rangle}{\partial x}$$

is explained in eq. (7) of my Phys.SE answer here. In short, eq. (1) is consistent with the corresponding bra equation

$$\langle x |\hat{p} ~=~-i\hbar \frac{\partial \langle x |}{\partial x} $$

via Hermitian conjugation. The bra equation in turn is related to OP's second equation

$$ \tag{2}\hat{p} ~=~ -i\hbar \frac{\partial }{\partial x} $$

via the standard convention

$$\psi(x)~=~\langle x | \psi \rangle$$

for the wave function.

--

$^1$ Both sides of the ket equation (1) are kets in an appropriate infinite-dimensional vector space. (Warning: not a Hilbert space, cf. e.g. this Phys.SE post and links therein.). One can multiply eq. (1) from left with a bra $\langle \psi |$ [belonging to an appropriate (possibly different) infinite-dimensional vector space] to achieve an equation

$$\hat{p}\psi(x)^{\ast} ~=~\langle \psi |\hat{p}|x\rangle ~\stackrel{(1)}{=}~+i\hbar\langle \psi |\frac{\partial }{\partial x}|x\rangle ~=~+i\hbar\frac{\partial \langle \psi |x\rangle}{\partial x}~=~+i\hbar\frac{\partial \psi(x)^{\ast}}{\partial x},$$

where both sides are complex numbers.

Added footnote 1
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Qmechanic
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OP's ket first equation$^1$

$$\tag{1} \hat{p}|x\rangle ~=~+i\hbar\frac{\partial |x\rangle}{\partial x}$$

is explained in eq. (7) of my Phys.SE answer here. In short, eq. (1) is consistent with the corresponding bra equation

$$\langle x |\hat{p} ~=~-i\hbar \frac{\partial \langle x |}{\partial x} $$

via Hermitian conjugation. The bra equation in turn is related to OP's second equation

$$ \tag{2}\hat{p} ~=~ -i\hbar \frac{\partial }{\partial x} $$

via the standard convention

$$\psi(x)~=~\langle x | \psi \rangle$$

for the wave function.

--

$^1$ Both sides of the ket equation (1) are kets in an appropriate infinite-dimensional vector space. (Warning: not a Hilbert space, cf. e.g. this Phys.SE post and links therein.). One can multiply eq. (1) from left with a bra $\langle \psi |$ [belonging to an appropriate (possibly different) infinite-dimensional vector space] to achieve an equation

$$\hat{p}\psi(x)^{\ast} ~=~\langle \psi |\hat{p}|x\rangle ~\stackrel{(1)}{=}~+i\hbar\langle \psi |\frac{\partial }{\partial x}|x\rangle ~=~+i\hbar\frac{\partial \langle \psi |x\rangle}{\partial x}~=~+i\hbar\frac{\partial \psi(x)^{\ast}}{\partial x},$$

where both sides are complex numbers.

OP's ket first equation

$$\tag{1} \hat{p}|x\rangle ~=~+i\hbar\frac{\partial |x\rangle}{\partial x}$$

is explained in eq. (7) of my Phys.SE answer here. In short, eq. (1) is consistent with the corresponding bra equation

$$\langle x |\hat{p} ~=~-i\hbar \frac{\partial \langle x |}{\partial x} $$

via Hermitian conjugation. The bra equation in turn is related to OP's second equation

$$ \tag{2}\hat{p} ~=~ -i\hbar \frac{\partial }{\partial x} $$

via the standard convention

$$\psi(x)~=~\langle x | \psi \rangle$$

for the wave function.

OP's ket first equation$^1$

$$\tag{1} \hat{p}|x\rangle ~=~+i\hbar\frac{\partial |x\rangle}{\partial x}$$

is explained in eq. (7) of my Phys.SE answer here. In short, eq. (1) is consistent with the corresponding bra equation

$$\langle x |\hat{p} ~=~-i\hbar \frac{\partial \langle x |}{\partial x} $$

via Hermitian conjugation. The bra equation in turn is related to OP's second equation

$$ \tag{2}\hat{p} ~=~ -i\hbar \frac{\partial }{\partial x} $$

via the standard convention

$$\psi(x)~=~\langle x | \psi \rangle$$

for the wave function.

--

$^1$ Both sides of the ket equation (1) are kets in an appropriate infinite-dimensional vector space. (Warning: not a Hilbert space, cf. e.g. this Phys.SE post and links therein.). One can multiply eq. (1) from left with a bra $\langle \psi |$ [belonging to an appropriate (possibly different) infinite-dimensional vector space] to achieve an equation

$$\hat{p}\psi(x)^{\ast} ~=~\langle \psi |\hat{p}|x\rangle ~\stackrel{(1)}{=}~+i\hbar\langle \psi |\frac{\partial }{\partial x}|x\rangle ~=~+i\hbar\frac{\partial \langle \psi |x\rangle}{\partial x}~=~+i\hbar\frac{\partial \psi(x)^{\ast}}{\partial x},$$

where both sides are complex numbers.

Added explanation
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Qmechanic
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OP's ket first equation (1)

$$\tag{1} \hat{p}|x\rangle ~=~+i\hbar\frac{\partial |x\rangle}{\partial x}$$

is explained in eq. (7) of my Phys.SE answer here. In short, thiseq. (1) is consistent with the corresponding bra equation $$\langle x |\hat{p} ~=~-i\hbar \frac{\partial \langle x |}{\partial x}.$$

$$\langle x |\hat{p} ~=~-i\hbar \frac{\partial \langle x |}{\partial x} $$

via Hermitian conjugation. The bra equation in turn is related to OP's second equation

$$ \tag{2}\hat{p} ~=~ -i\hbar \frac{\partial }{\partial x} $$

via the standard convention

$$\psi(x)~=~\langle x | \psi \rangle$$

for the wave function.

OP's ket equation (1) is explained in eq. (7) of my Phys.SE answer here. In short, this is consistent with the corresponding bra equation $$\langle x |\hat{p} ~=~-i\hbar \frac{\partial \langle x |}{\partial x}.$$

OP's ket first equation

$$\tag{1} \hat{p}|x\rangle ~=~+i\hbar\frac{\partial |x\rangle}{\partial x}$$

is explained in eq. (7) of my Phys.SE answer here. In short, eq. (1) is consistent with the corresponding bra equation

$$\langle x |\hat{p} ~=~-i\hbar \frac{\partial \langle x |}{\partial x} $$

via Hermitian conjugation. The bra equation in turn is related to OP's second equation

$$ \tag{2}\hat{p} ~=~ -i\hbar \frac{\partial }{\partial x} $$

via the standard convention

$$\psi(x)~=~\langle x | \psi \rangle$$

for the wave function.

Minor
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Qmechanic
  • 213.1k
  • 48
  • 590
  • 2.3k
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Source Link
Qmechanic
  • 213.1k
  • 48
  • 590
  • 2.3k
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