I have attached the question as a picture. I simply don't understand where to begin this question. It is given that $l > > d$$l \gg d$. Why shouldn't the phase difference at $O$ be zero? What exactly is different about this set-up as compared to the 'normal' set-up of YDSEYoung's Double Slit experiment?
I have attached the question as a picture. I simply don't understand where to begin this question. It is given that $l > > d$. Why shouldn't the phase difference at $O$ be zero? What exactly is different about this set-up as compared to the 'normal' set-up of YDSE?
I have attached the question as a picture. I simply don't understand where to begin this question. It is given that $l \gg d$. Why shouldn't the phase difference at $O$ be zero? What exactly is different about this set-up as compared to the 'normal' set-up of Young's Double Slit experiment?
I have attached the question as a picture. I simply don't understand where to begin this question. It is given that $l > > d$. Why shouldn't the phase difference at $O$ be zero? What exactly is different about this set-up as compared to the 'normal' set-up of YDSE?
