Timeline for Bohr Model of the Hydrogen Atom - Energy Levels of the Hydrogen Atom
Current License: CC BY-SA 3.0
8 events
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Aug 22, 2015 at 18:28 | comment | added | anna v | Physics ultimately does not answer why. why end up on the postulates of quantum mechanics which were chosen so that the observed behavior is fitted. The answer then is "because that is the way nature behaves and is well modeled by QM" | |
Aug 22, 2015 at 15:51 | comment | added | Nukul Parmar | As you said it is a probabilistic energy cloud then here electron will have same energy( not taking about excited state) agree and as it is a energy cloud there will be energy( you will also agree this). Then why is this energy cloud always remain in that form for all the time? Why don't they turn into mass or other forms of energy. I am not at all taking about excited states. | |
Aug 22, 2015 at 15:43 | comment | added | Nukul Parmar | can you please explain me in detail the word you used as energy operator. | |
Aug 22, 2015 at 2:53 | comment | added | anna v | systems tend to the ground state, by radiating away physics.stackexchange.com/questions/201674/… . The cloud image is a representation of the probability density to find an electron at (x,y,z) when measuring it. Not an energy cloud, a probabilistic energy cloud. | |
Aug 22, 2015 at 2:47 | comment | added | anna v | equations do not tell that there is an energy cloud. Equations tell us that there exist energy levels fitted/modeled with the wavefunction. The energy operator operating on the wave function will give the energy of that level. | |
Aug 21, 2015 at 21:44 | comment | added | Nukul Parmar | Thanks Anna v for enlighten me but you didn't got my actual question. I accidently gave the topic as Bohr model. I wrote orbitals and I mean that they are orbitals and I am not taking about orbits. Ok. I actually mean that why they are stationary? If it is just equations told that then why equations told that there is and energy cloud called orbitals? What helps that energy to stay there and from where it come from? | |
Aug 20, 2015 at 20:41 | comment | added | Gert | Actually, the square of the wave function gives you the probability density at a specific (x,y,z). $ψ^2 (x,y,z)$ needs to be integrated over a space interval to give the actual probability of finding the electron in that area of space. The probability of finding the electron in a specific location (x,y,z) is actually zero. | |
Aug 20, 2015 at 19:56 | history | answered | anna v | CC BY-SA 3.0 |