An incompressible inviscid fluid is rotating under gravity g with constant angular velocity $Ω$$\Omega$ about the z-axis, which is vertical, so that $u = (−Ωy, Ωx, 0)$$u = (−\Omega y, \Omega x, 0)$ relative to fixed Cartesian axes. We wish to find the surfaces of constant pressure, and hence surface of a uniformly rotating bucket of water (which will be at atmospheric pressure). Bernoulli's equation suggests that $$p/\rho+|u|^2/2+gz=constant$$ so$$p/\rho+|u|^2/2+gz=\text{constant. So,}$$
$$z=constant-\frac{Ω^2}{2g}(x^2+y^2)$$$$z=\text{constant}-\frac{\Omega^2}{2g}(x^2+y^2)$$
But this suggests that the surface of a rotating bucket of water is at its highest in the middle, where is this going wrong?
Many thanks