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Qmechanic
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If Lagrangian, $\mathscr L = \dot{q}^2 - q \dot{q}$. Then what can be inferred about the particle?

simplySimply that it is a free particle or something else?

If Lagrangian, $\mathscr L = \dot{q}^2 - q \dot{q}$. Then what can be inferred about the particle?

simply that it is a free particle or something else?

If Lagrangian, $\mathscr L = \dot{q}^2 - q \dot{q}$. Then what can be inferred about the particle?

Simply that it is a free particle or something else?

Post Reopened by Qmechanic
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If Lagrangian, $\mathscr L = \dot{q}^2 - q \dot{q}$. Then what can be inferred about the particle?

simply that it is a free particle or whatsomething else?

If Lagrangian, $\mathscr L = \dot{q}^2 - q \dot{q}$. Then what can be inferred about the particle?

simply that it is a free particle or what else?

If Lagrangian, $\mathscr L = \dot{q}^2 - q \dot{q}$. Then what can be inferred about the particle?

simply that it is a free particle or something else?

symbol for derivative with respect to time t
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If Lagrangian, $\mathscr L = (q^*)^2 - q(q^*)$$\mathscr L = \dot{q}^2 - q \dot{q}$. Then what can be inferred about the particle?

simply that it is a free particle or what else?

If Lagrangian, $\mathscr L = (q^*)^2 - q(q^*)$. Then what can be inferred about the particle?

simply that it is a free particle or what else?

If Lagrangian, $\mathscr L = \dot{q}^2 - q \dot{q}$. Then what can be inferred about the particle?

simply that it is a free particle or what else?

Post Closed as "Needs details or clarity" by Qmechanic
added MathJax and improved the title
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Jim
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