Timeline for Number $g(T)$ of relativistic degrees of freedom as a function of temperature $T$
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Oct 7, 2022 at 17:45 | comment | added | Aslan Monahov | What g should I take between 500 KeV and 1MeV? | |
| Jan 31, 2020 at 16:10 | comment | added | Jasmeru | I know this is a bit late, but the answer might still be useful for some people. If I'm not mistaken it's because the QCD phase transition occurs around $T\sim200$ MeV. At this moment quarks are not longer free, they are bound in baryons (protons and neutrons) with masses $\sim 1$ GeV $>T$ and they no longer behave like relativistic particles. | |
| Nov 19, 2019 at 4:42 | comment | added | Juan Pablo Arcila | Excuse me, how is it that below 100 MeV all quarks stop being relativistic, when s,d and u quark have rest energy less than 100 MeV? | |
| Mar 17, 2015 at 1:47 | vote | accept | Kagaratsch | ||
| Mar 17, 2015 at 0:19 | history | edited | Pulsar | CC BY-SA 3.0 |
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| Mar 16, 2015 at 15:08 | history | edited | Pulsar | CC BY-SA 3.0 |
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| Mar 16, 2015 at 15:02 | history | answered | Pulsar | CC BY-SA 3.0 |