Timeline for Time-dependence of ladder operators in quantized EM fields
Current License: CC BY-SA 3.0
13 events
when toggle format | what | by | license | comment | |
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Jun 19, 2016 at 10:57 | vote | accept | sagittarius_a | ||
Mar 7, 2015 at 21:50 | comment | added | dolun | See the edit $\uparrow$ for discussion purpose. | |
Mar 7, 2015 at 21:49 | history | edited | dolun | CC BY-SA 3.0 |
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Mar 7, 2015 at 20:50 | comment | added | sagittarius_a | If it's not in Heisenberg picture and you transform to it the frequency doubles | |
Mar 7, 2015 at 20:46 | comment | added | sagittarius_a | Okay. But as a matter of fact I get a time dependence in the EM field. So. Is it now an operator in Heisenberg picture or not? | |
Mar 7, 2015 at 20:44 | comment | added | dolun | Once again, you don't land in any peculiar picture while performing quantization. These are two different stories. | |
Mar 7, 2015 at 20:37 | comment | added | sagittarius_a | The problem is: in which picture do you land when you perform the quantization | |
Mar 7, 2015 at 20:36 | comment | added | dolun | Yes and what exactly is the problem with that? All different QM pictures are unitary equivalent since probabilities are conserved in the process. The way the field is quantized is independant of the picture one can use to treat time-dependance. | |
Mar 7, 2015 at 20:28 | comment | added | sagittarius_a | Exactly. If you quantize the EM field, all ladder operations appear already as operators in the Heisenberg picture would appear . | |
Mar 7, 2015 at 20:26 | comment | added | dolun | I'm confused. What are you exactly calling "Heisenberg operators"? Are you referring to the Heisenberg picture of the operators $a$ and $\sigma_\pm$? | |
Mar 5, 2015 at 10:32 | comment | added | sagittarius_a | Thank you for your elaborate answer. However I am not completely happy since I am still confused why the quantization procedure yields the Heisenberg operators already.. | |
Mar 4, 2015 at 14:01 | history | edited | dolun | CC BY-SA 3.0 |
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Mar 4, 2015 at 13:42 | history | answered | dolun | CC BY-SA 3.0 |