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What is important for tidal forces is not the absolute gravity, but the differential gravity across the planet, that is, how different the gravity is at a point on the surface near the sun relative to a point on the other side. Because the Sun is far away, gravity doesn't change much between the two extremes on earth. However, if you compare it with the moon, because the sun is much heavier, the result will be that the tidal force from the sun is about 0.43 that of the moon.

This is because if two bodies have the same apparent size in the sky, like the moon and the sun, then the mass M of the object will grow as $r^3$ (because $M=4/3\rho\pi R^3$ and $R=\theta r$), so the force actually grows linearly with $r$. Where $r$ is the distance and $R$ is the radius of the object. So if the moon and the sun had the same density, the tidal force would be the same. The density of the moon is about 2.3 times larger than that of the sun, that is why the tidal force is larger by that factor.

What is important for tidal forces is not the absolute gravity, but the differential gravity across the planet, that is, how different is the force of gravity at a point on the Earth's surface near the sun relative to a point on the Earth's surface far from the sun. If you compare it with the moon, the result will be that the tidal force from the sun is about 0.43 that of the moon.

Suppose two different bodies in the sky that have the same apparent size. Because the mass M of the object will grow as $r^3$ (because $M=4/3\rho\pi R^3$ and $R=\theta r$), the gravitational force will actually grow linearly with $r$, where $r$ is the distance and $R$ is the radius of the object. So if two bodies have the same apparent size (such as the Moon and the Sun) and the same density, the tidal force would be the same. The density of the moon is about 2.3 times larger than that of the sun, that is why the tidal force is larger by that factor.

What is important for tidal forces is not the absolute gravity, but the differential gravity across the planet, that is, how different the gravity is at a point on the surface near the sun relative to a point on the other side. Because the Sun is far away, gravity doesn't change much between the two extremes on earth. However, if you compare it with the moon, because the sun is much heavier, the result will be that the tidal force from the sun is about 0.43 that of the moon.

This is because if two bodies have the same apparent size in the sky, like the moon and the sun, then the mass M of the object will grow as $r^3$ (because $M=4/3\rho\pi R^3$ and $R=\theta r$), so the force actually grows linearly with $r$. Where $r$ is the distance and $R$ is the radius of the object. So if the moon and the sun had the same density, the tidal force would be the same. The density of the moon is about 2.3 times larger than that of the sun, that is why the tidal force is larger by that factor.

What is important for tidal forces is not the absolute gravity, but the differential gravity across the planet, that is, how different the gravity is at a point on the surface near the sun relative to a point on the other side. Because the Sun is far away, gravity doesn't change much between the two extremes on earth. However, if you compare it with the moon, because the sun is much heavier, the result will be that the tidal force from the sun is about 0.43 that of the moon.

This is because if two bodies have the same apparent size in the sky, like the moon and the sun, then the mass M of the object will grow as $r^3$ (because $M=4/3\rho\pi R^3$ and $R=\theta r$), so the force actually grows linearly with $r$. Where $r$ is the distance and $R$ is the radius of the object. So if the moon and the sun had the same density, the tidal force would be the same. The density of the moon is about 2.3 times larger than that of the sun, that is why the tidal force is larger by that factor.

What is important for tidal forces is not the absolute gravity, but the differential gravity across the planet, that is, how different the gravity is at a point on the surface near the sun relative to a point on the other side. Because the Sun is far away, gravity doesn't change much between the two extremes on earth. However, if you compare it with the moon, because the sun is much heavier, the result will be that the tidal force from the sun is about 0.43 that of the moon.

This is because if two bodies have the same apparent size in the sky, like the moon and the sun, then the mass M of the object will grow as $r^3$ (because $M=4/3\rho\pi R^3$ and $R=\theta r$), so the force actually grows linearly with $r$. Where $r$ is the distance and $R$ is the radius of the object. So if the moon and the sun had the same density, the tidal force would be the same. The density of the moon is about 2.3 times larger than that of the sun, that is why the tidal force is larger by that factor.

What is important for tidal forces is not the absolute gravity, but the differential gravity across the planet, that is, how different the gravity is at a point on the surface near the sun relative to a point on the other side. Because the Sun is far away, gravity doesn't change much between the two extremes on earth. However, if you compare it with the moon, because the sun is much heavier, the result will be that the tidal force from the sun is about 0.43 that of the moon.

This is because if two bodies have the same apparent size in the sky, like the moon and the sun, then the mass M of the object will grow as $r^3$ (because $M=4/3\rho\pi R^3$ and $R=\theta r$), so the force actually grows linearly with $r$. Where $r$ is the distance and $R$ is the radius of the object. So if the moon and the sun had the same density, the tidal force would be the same. The density of the moon is about 2.3 times larger than that of the sun, that is why the tidal force is larger by that factor.