What is important for tidal forces is not the absolute gravity, but the differential gravity across the planet, that is, how different the gravity is  at a point on the surface near the sun relative to a point on the other side. 
Because  the Sun is far away, gravity doesn't change much between the two extremes on earth. However, if you compare it with the moon, because the sun is much heavier, the result will be that the tidal force from the sun is about 0.43 that of the moon. 

This is because if two bodies have the same apparent size in the sky, like the moon and the sun,  then the mass M of the object will grow as $r^3$ (because $M=4/3\rho\pi R^3$ and $R=\theta r$), so the force actually grows linearly with $r$. Where $r$ is the distance and $R$ is the radius of the object. So if the moon and the sun had the same density, the tidal force would be the same. The density of the moon is about 2.3 times larger than that of the sun, that is why the tidal force is larger by that factor.

![Sun and Moon tidal force][1]


  [1]: https://i.sstatic.net/ViJMB.gif