Alpha001
• Member for 6 years, 2 months
• Last seen more than 1 year ago
• Germany

You can think of it in such a way. Let $\phi(x)$ be the potential function of an electric field $\vec{E}$ with boundary conditions $\lim\limits_{x\to \infty} \phi(x) = 0$. For the potential we obtain ...

The momentum is given by: $$p = \int_{t_0}^{t_1} dt F(t)$$ The change of momentum $\dot{p}(t)$ is therefore related to the force $F(t)$. If you want you can say that in some sense your statement ...

It is a change of view. In the Schrödinger picture your operator is not time dependet (or only explicitly time dependent) but your states evolve with time. On the other side in the Heisenberg picture ...

Let's try to summarize the characteristics of the $\gamma$-matrices and the metric tensor for flat Minkowski space. First our $\eta^{\mu\nu}$ can be represented by the matrix $$\eta^{\mu\nu} = \... View answer 1 votes Maybe the term "orbiting" causes some problems. The electron is not moving around the nucleus as bohr assumed (he had no solution according to the problem that an electron on a circular orbit should ... View answer 1 votes By newton's law you will find for the force of the pendulum without friction and gravity:$$m\ddot{x} = -kx  For this you get the solution: $x(t) = A \cdot sin(\omega \cdot t)$. Where $\omega = \... View answer 1 votes Indeed we have to implement the CCR or CAR as an axiom to QM/QFT. But if you like to think about it in terms of an action principle look at Schwinger's quantum action principle. From this axiom you ... View answer 1 votes There exists something called fermi or bose gas which consits of fermions or bosons. In some sense you can say that this is like a substance. The question is does it exists in the universe? The ... View answer 0 votes Assume a body with mass$m+M$and velocity$\vec{v}_0$its momentum is given by$\vec{p}_0 = (m+M)\vec{v}_0$: If the body losses mass$m$(assuming instantanously) and the mass$m$moves with$\vec{...