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Avi
  • Member for 8 years, 2 months
  • Last seen more than 4 years ago
  • Khopoli ST Bus Stand, Laxminagar, Khopoli, Maharashtra, India
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Work done involving friction and other external forces
Thanks for your effort but please take effort one more time for me. I have edited my question including one more question as you said to use $wf$ negative but in the another similar question using +ve value gives me right answer there. Please read the question.
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Work done involving friction and other external forces
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Work done involving friction and other external forces
I have done that only in my last equation, taking Initial P.E= mgH, final P.E=mgh and final heat energy=Wf. Hence $mgH=mgh+Wf$ which gave me wrong answer for Wf.
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Work done involving friction and other external forces
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Condition for Maximum Power in the circuit
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Intensity Of Sound
I just want to know that if you have been given all numerical values of all variables in the equation (ii). Example value of each variable in equation (ii) is 1 and you are asked to find out intensity of wave at a distance of 5m from the source using equation (ii) then how will you find it.
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Intensity Of Sound
from your conclusion, $Sm=S0/r^2$, i.e. we can say that amplitude Sm is inversely proportional to square of distance from source. but we know intensity (I) is directly proportional to square of amplitude ($Sm^2$) and also from my first equation (I) is inversely proportional to ($r^2$). from these two we get $Sm^2$ is inversely proportional to $r^2$ i.e Sm is inversely proportional to r, which is against your conclusion that Sm is inversely proportional to $r^2$. Please explain
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Intensity Of Sound
'V' is velocity of the wave in the medium, 'w2' is the angular velocity of wave and the that remaining one is the density of given medium.
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Equivalent resistance
thanks for your respond Michael but you said that voltage drop across first resistor will be same in both the legs, but how it could be as one branch is having 1 ohm and another one is having 2 ohm.