Skip to main content
jake walsh's user avatar
jake walsh's user avatar
jake walsh's user avatar
jake walsh
  • Member for 8 years, 10 months
  • Last seen this week
awarded
awarded
comment
Weinberg's proof that $F^{\alpha \beta}$ is a tensor
I think I understand, thank you.
comment
Weinberg's proof that $F^{\alpha \beta}$ is a tensor
In regards to my einstein or tensor question, I could be wrong but I think they are the same thing. We use tensors precisely for the reason that they do what the einstien postulate wants,that is the equations take the same form in a any lorentz frame. Is this correct?
comment
Weinberg's proof that $F^{\alpha \beta}$ is a tensor
Yes, I think I understand. If we do a lorentz transform and require that the equation remain the same(not sure if this is an einstein postulate or a tensor thing) we have $\frac{\partial}{\partial x^{'\alpha}} F^{' \alpha \beta} = -J^{' \beta}$. So that $\Lambda_{\alpha}^{\gamma} \frac{\partial}{\partial x^{\gamma}} F^{' \alpha \beta} = \Lambda^{\beta}_{\delta}J^{\delta}$ iff $F^{' \alpha \beta} = \Lambda^{\alpha}_{\gamma} \Lambda^{\beta}_{\delta} F^{\gamma \delta}$. Is this the line of reasoning?
Loading…
Loading…
comment
If the curve a particle moves in when calculating work is dependent on the force itself, why don't we find this path before doing work calculations?
So a more hands on work calculation could consist of giving multiple forces, finding the net force, applying newtons laws to find the trajectory of the particle then calculating the work done by one of these forces or the net force. Is this correct?
comment
If the curve a particle moves in when calculating work is dependent on the force itself, why don't we find this path before doing work calculations?
Thank you for you answer, in regards to your last paragraph have I understood this right? There may be multiple forces acting to give us the specific curve given but we are calculating the work done by one specific force along this curve?
awarded
Loading…
awarded
awarded
comment
Relative Velocity and Mass
Am I correcet in saying that when we simplying add velocities like that we assume the acceleration is instant then?
accepted
asked
Loading…