19
votes
Accepted
Since water is a molecule, can the aerosol sprayed through double slit form interference pattern?
No, not with a spray.
The reason for this is that "sprays" are not isolated molecules. They are fine droplets, and the individual droplets are still vastly larger than a molecule - a ...
- 19.9k
10
votes
Why does more ice melt slower than less ice?
Water has heat of fusion about $ H_{fus} =80~\text{cal/g}$, this means that for melting 1 gram of ice you need about 80 calories of heat. Obviously having more ice (monolithic piece or fragmented ...
- 11.6k
9
votes
Why does more ice melt slower than less ice?
The reason is still basically a variation of the square cube law. A pile or cup of ice cubes have more volume to melt relative to the effective surface area to perform heat transfer compared to if you ...
- 9,014
7
votes
Since water is a molecule, can the aerosol sprayed through double slit form interference pattern?
The deBroglie wavelength of a droplet of water can be calculated like any other particle:
$$\lambda = \frac{h}{mv}$$
Where $h = 6.62607015×10^{-34} \frac{J}{Hz}$ - at $100 \frac{m}{s}$ a 1000 nm ...
- 4,225
4
votes
Since water is a molecule, can the aerosol sprayed through double slit form interference pattern?
They have performed interference experiments with big molecules, but not in forms of sprays, since then collisions and interactions between the particles would lead to their decoherence and loss of ...
- 59
2
votes
Why does more ice melt slower than less ice?
Hey I think the statement: ice cubes that are larger melt slower because of their surface area is not truly correct. you know greater the surface (through which heat transfer occurs) lesser will be ...
- 61
1
vote
Since water is a molecule, can the aerosol sprayed through double slit form interference pattern?
Every "entity" with mass has an associated deBroglie wavelength λ = h/mv. But because m is (relatively) large for droplets, λ becomes very small. But if you squint, even relatively large ...
- 3,933
1
vote
Accepted
Difference between Kopp-Neumann and Dulong-Petit law?
I'm not sure how you'd apply Kopp-Neumann in this case - you have no mixture...
However, as to Dulong-Petit, note that it assumes quadratic degrees of freedom, and localized particles. Therefore it is ...
- 26
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