7
votes
Accepted
Why is the Riemann curvature tensor not zero?
I cannot see the problem. Fix $p\in M$, then $$(R^d_{cab}V^c)_p=((\nabla_a\nabla_b-\nabla_b\nabla_a)V^d)_p$$
implies that $(R^d_{cab}V)_p=0$ if the vector field $V$, defined in a neighborhood $U_p$ ...
4
votes
What are some ways to derive $\left( \boldsymbol{E}\cdot \boldsymbol{E} \right) \nabla =\frac{1}{2}\nabla \boldsymbol{E}^2$?
Your second equation with its $({\bf E}\cdot {\bf E})\nabla$ isnot really correct as the nabla has to act on one of the ${\bf E}$'s. The correct form is best written as $({\bf E} \cdot \nabla {\bf E})...
3
votes
Why is the Riemann curvature tensor not zero?
I think the OP is correct to call $V^d$ as a vector field rather than a vector. Say we define covariant derivative
$$ \nabla_X Y$$
Then, while evaluating the covariant derivative at a point $p$, it is ...
2
votes
How to calculate the rotation at a singularity?
Just to give a few hints:
The strategy is usually to use a theorem that says that two integrals must be equal.
In your case the classical Gauss' and Stokes' theorems don't seem to work but some hope I ...
1
vote
Accepted
Can a non-zero curl vector force field still do a null amount of work?
Question 1:
Recall from Stokes' theorem that $$\oint \vec{F} \cdot d\vec{l} = \int (\vec{\nabla} \times \vec{F}) \cdot d\vec{a}.$$So any path that can be spanned by a surface for which this latter ...
1
vote
Is the Lorentz force a vector field or just a vector?
The force pertains to a charged body moving along a trajectory given by the equation $𝐫 = 𝐑(t)$, where I'm going to denote the function by a separate letter to remove the confusion. The velocity is $...
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