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-1 votes

Solving for deceptively simple two-block pulley system

We can analyse the forces acting on each pulley, which must add up to $0$ assuming the ropes and pulleys have no mass. It is obvious that there’s no physical solution to this problem without ...
Jono94's user avatar
  • 471
-1 votes

Solving for deceptively simple two-block pulley system

Let's define coordinates: $m$ has $x_1$, $2m$ has $x_2$ and the block above $m$ has $x_0$. Overall length of the string will therefore be expressed: $$ l = 2x_2 + x_1 - x_0 $$ Differentiating this ...
goroshek's user avatar
  • 180
3 votes

How can we prove that tension on both sides of string will be equal?

The string is massless and inextensible; so if there is a net force on any part of the string it will cause its acceleration. Since m approaches zero, acceleration for even a small unbalanced force ...
Stuti Gupta's user avatar
0 votes

How can we prove that tension on both sides of string will be equal?

Let me put it one more way: If the tensions at two points of the string were different, the string piece between these two points would experience a net force from the tension difference. There are no ...
Ralf Kleberhoff's user avatar
6 votes
Accepted

How can we prove that tension on both sides of string will be equal?

$\dots$ the tension on both sides of mass $m$ will be equal $\dots$ if there is no friction between the bead and the string. If there are no frictional forces then the fact that the string is massless ...
Farcher's user avatar
  • 93.4k
4 votes

How can we prove that tension on both sides of string will be equal?

The phrase "inextensible string" and the fact it's tied down at a point, is what determines that the tension at every point along the string is the same: "Inextensible" doesn't ...
Nadav Har'El's user avatar
  • 2,211
8 votes

How can we prove that tension on both sides of string will be equal?

"A massless inextensible string wearing a bead of mass m" From this line I assume there is only one string used throughout, and is passed through the hollow centre of the bead. As long as ...
Schrödinger's Cat's user avatar
1 vote
Accepted

Newton's globe experiment with linear acceleration?

To ensure that there is no relative motion in the case of linearly accelerated motion, the same amount of force must act at every point of the moving body. If this is the case, there is no noticeable ...
wutzi's user avatar
  • 21
0 votes

Three masses connected by a string (momentum conservation)

Note sure why you think A will collide with B, or what "collide without contact" means. My interpretation of the scenario is that B moves in the positive $y$ direction, A and C are pulled ...
gandalf61's user avatar
  • 47.4k
0 votes
Accepted

Three masses connected by a string (momentum conservation)

Firstly, the net external force acting on the system (all 3 bodies) is zero, which means that you are free to use the laws of conservation of energy and momentum. You need to understand that the ...
Sai Aditya's user avatar
1 vote

How is the curvature of a vibrating string defined in classical mechanics?

By definition curvature is differential angular displacement vs differential arc length. $\kappa = \frac{d \theta}{ds}$ $\tan \theta = y'\implies \sec ^2\theta (d\theta /dx) = y''\implies \frac{d \...
R. Romero's user avatar
  • 2,500
2 votes

How is the curvature of a vibrating string defined in classical mechanics?

I am not sure to understand the question. Also because two comments by Ghoster already implicitly answered the same. However, the curvature is, by definition, the inverse of the curvature radius. The ...
Valter Moretti's user avatar
0 votes

Determining the equations of motion for a 2 DOF in 2 directions

You are correct in trying to establish the equivalent mass of the pulley $m_p$ and place it inline with the rest of the system You can work out what $m_p$ should be by taking the pulley at rest and ...
John Alexiou's user avatar
  • 37.4k
2 votes

Where would a string with multiple points of equal weakness break?

As you pull from both ends, the string begins to accelerate and stretch slightly. The stretching force propagates through the string at the speed of sound - there is a period of time where the middle ...
Nuclear Hoagie's user avatar
1 vote

Where would a string with multiple points of equal weakness break?

Force propagates through the string at the speed of sound (in the string). So your final assumption would be correct. The outermost weak points will feel the pull before the more distant weak points ...
foolishmuse's user avatar
  • 4,221
0 votes

Tension in a vibrating loop

Your first equation that states frequency is velocity divide by wave length. But this is not a basic law of motion but in fact is just a definition. It assumes there is a trigonometric function. Then ...
Terence Allen's user avatar
-1 votes

String vibration and damping

First, the question contains an error because it assumes the initial condition of the string is determined by an “arbitrary initial condition” but the initial condition is the string length and ...
Terence Allen's user avatar
0 votes

How does a string thickness affect the frequency of its harmonics?

The ideal string has: $$ f_n = nf_0 $$ for the $n$-th harmonic. Including a finite thickness modifies that to: $$ f_n = nf_0\sqrt{1+Bn^2}\big(1+\frac 2{pi}\sqrt B + \frac 4{\pi} B\big) $$ with $$B = \...
JEB's user avatar
  • 31.4k
0 votes

Deriving the longitudinal sound wave from the transverse string vibration

The sound waves are produced by a moving surface that is the minimum surface of revolution formed by the string orbit. Your graph has the correct curve but the orbit of the string is that curve ...
Terence Allen's user avatar
0 votes

How does a string thickness affect the frequency of its harmonics?

Generally you try to excite many harmonics when you play an instrument. You can see this by the fact that a piano hammers the strings near the end. Likewise a guitar or violin. The strings do not ...
mmesser314's user avatar
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