# Tag Info

### Solving for deceptively simple two-block pulley system

We can analyse the forces acting on each pulley, which must add up to $0$ assuming the ropes and pulleys have no mass. It is obvious that there’s no physical solution to this problem without ...

### Solving for deceptively simple two-block pulley system

Let's define coordinates: $m$ has $x_1$, $2m$ has $x_2$ and the block above $m$ has $x_0$. Overall length of the string will therefore be expressed: $$l = 2x_2 + x_1 - x_0$$ Differentiating this ...

### How can we prove that tension on both sides of string will be equal?

The string is massless and inextensible; so if there is a net force on any part of the string it will cause its acceleration. Since m approaches zero, acceleration for even a small unbalanced force ...

### How can we prove that tension on both sides of string will be equal?

Let me put it one more way: If the tensions at two points of the string were different, the string piece between these two points would experience a net force from the tension difference. There are no ...
Accepted

### How can we prove that tension on both sides of string will be equal?

$\dots$ the tension on both sides of mass $m$ will be equal $\dots$ if there is no friction between the bead and the string. If there are no frictional forces then the fact that the string is massless ...

### How can we prove that tension on both sides of string will be equal?

The phrase "inextensible string" and the fact it's tied down at a point, is what determines that the tension at every point along the string is the same: "Inextensible" doesn't ...

### How can we prove that tension on both sides of string will be equal?

"A massless inextensible string wearing a bead of mass m" From this line I assume there is only one string used throughout, and is passed through the hollow centre of the bead. As long as ...
1 vote
Accepted

### Newton's globe experiment with linear acceleration?

To ensure that there is no relative motion in the case of linearly accelerated motion, the same amount of force must act at every point of the moving body. If this is the case, there is no noticeable ...

### Three masses connected by a string (momentum conservation)

Note sure why you think A will collide with B, or what "collide without contact" means. My interpretation of the scenario is that B moves in the positive $y$ direction, A and C are pulled ...
Accepted

### Three masses connected by a string (momentum conservation)

Firstly, the net external force acting on the system (all 3 bodies) is zero, which means that you are free to use the laws of conservation of energy and momentum. You need to understand that the ...
1 vote