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Is the 2nd law a reason for the irreversibility of natural processes or a consequence of it?

So, is entropy just a function to describe the nature and has no say on the cause behind the observations about irreversibility of natural processes? That's right. Entropy is a concept, a function of ...
Ján Lalinský's user avatar
1 vote

Use of Clausius theorem to prove entropy inequality in Fermi's Thermodynamics

The easiest way to understand the Clausius inequality is to recognize that entropy is a state function and that, for a closed system (no mass in or out during a process between two thermodynamic ...
Chet Miller's user avatar
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0 votes

Entropy in irreversible adiabtic process

But , we know that between two themodynamic states there exists many reversible paths becauseof which the value of $δQ_{rev}$ can vary beacuse of heat being a path function which will then lead to ...
Bob D's user avatar
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1 vote

Use of Clausius theorem to prove entropy inequality in Fermi's Thermodynamics

If we trust that temperature is a positive quantity and heat "goes from hot bodies to cold bodies", everything should follow quite naturally. In this answer, I'm focusing on the elementary ...
basics's user avatar
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4 votes
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Use of Clausius theorem to prove entropy inequality in Fermi's Thermodynamics

With all this in mind, to which 'part' of the universe (i.e., the system or the surroundings) is Fermi referring when he writes (in his notation) $$ 0 \ge \oint \frac{\mathrm{d}Q}{T} =…$$ The ...
Bob D's user avatar
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7 votes

Use of Clausius theorem to prove entropy inequality in Fermi's Thermodynamics

All mysteries go away if you realize that when you say $dQ$ (or $\delta Q$) heat is supplied from the reservoir whose temperature is $T_e$ then along with said heat the reservoir supplies $dS_e=\frac{\...
hyportnex's user avatar
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2 votes

Use of Clausius theorem to prove entropy inequality in Fermi's Thermodynamics

Start by the definition of entropy. By definition: $$ S(B)-S(A) = \int_{Rev,\,A\to B}\frac{\delta Q}{T_e} $$ for any reversible path from $A\to B$. The definition is well posed since Clausius' ...
LPZ's user avatar
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-1 votes

What is the relationship between Clausius Inequality and 2nd Law?

The Clausius inequality applies to a closed system, and does not include the surroundings. The more correct form of this inequality is $$\Delta S_{syst}\geq \int{\frac{dQ}{T_B}}$$where $T_B$ is the ...
Chet Miller's user avatar
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