# Tag Info

### Do liquids typically solidify under enough pressure?

The example you have chosen to start your question (water) is an atypical case. The phase diagram has a logarithmic scale for the pressure, somewhat hiding the negative slope of the transition line ...

1 vote

### If an object suspended by a string is immersed in a liquid, will its weight contribute to the pressure at the bottom of the container?

Assuming the set-up is in equilibrium, and that the atmospheric pressure is zero, the tension in the string would balance the apparent weight of the sphere (the apparent weight being mg-buoyant force)....
1 vote
Accepted

### Sum of two state functions is not path independent

I would venture to offer a simple formal explanation of why the arguments leading to the paradoxical inequality of mixed partial derivatives of the state function are incorrect. There were adequate ...
1 vote

### Do liquids typically solidify under enough pressure?

No, there are some substances which never become solids. One example: He. If we have 3He, it will form a Bose-Einstein condensate if I remember correctly.
1 vote

### Bird feeder - hydrostatic equilibium

Put the lid on and shut it airtight. If you put a hole in at any level, air will flow in and water will flow out. The level of the spigot determines the water level if there is no air hole. Water can ...
1 vote
Accepted

### Is buoyancy affected by container geometry?

The generally accepted answer is "no", simply by application of Archimedes buoyancy principle, but there are limits. Firstly, if you make your container long enough and thin enough, and ...
1 vote

### Enthalpy of a Van der Waals gas continuation

If you know the initial and final states of the gas, it is easier to get the enthalpy change for a VDW gas by working with the internal energy change $\Delta U$ than $\Delta H$. This is because the ...
1 vote

### Enthalpy of a Van der Waals gas continuation

Your equation is wrong. It should read $$dH=\left(V-T\left(\frac{\partial V}{\partial T}\right)_P\right)dP$$ You may have to integrate this numerically because of the non-linearity with of the VDW ...
1 vote

### Height of a stable droplet on a perfectly wetting surface, shape of a water drop

If I understand your elaborations correctly, your problem is this: Since the surface is perfectly wetting¹, the contact angle in the typical sense does not matter since there is no point at which the ...

Only top scored, non community-wiki answers of a minimum length are eligible