8
votes
Do liquids typically solidify under enough pressure?
The example you have chosen to start your question (water) is an atypical case. The phase diagram has a logarithmic scale for the pressure, somewhat hiding the negative slope of the transition line ...
3
votes
Is buoyancy affected by container geometry?
Let's an imaginary vertical cylinder, with a very small radius, crossing the bottom and top surface of an object. The net upward force, disregarding internal stresses inside the object is:
$$\frac{P_{...
3
votes
Is buoyancy affected by container geometry?
No--not if the containers when submerged both displace the same amount of fluid, and if the empty containers have the same weight. If one sinks the other will sink.
2
votes
Is buoyancy affected by container geometry?
In a word, "No." Buoyancy depends only on the relative densities of the object and the fluid in which it is immersed.
I confess, I don't know how to prove it. But I'm pretty sure that the ...
2
votes
Water Vapour and Liquid Water Interactions
There is absolutely nothing stopping them, and in fact water molecules are constantly hopping between the phases to a degree dictated by the temperature of the system. The proper term used to describe ...
2
votes
Accepted
Find the ideal gas law from the internal energy
I am not totally sure if this is the most straightforward way, but you will receive the ideal gas law by varying $U$, that is
$$\operatorname{d}U = \dfrac{\partial U}{\partial V} \operatorname{d}V + \...
1
vote
If an object suspended by a string is immersed in a liquid, will its weight contribute to the pressure at the bottom of the container?
Assuming the set-up is in equilibrium, and that the atmospheric pressure is zero, the tension in the string would balance the apparent weight of the sphere (the apparent weight being mg-buoyant force)....
1
vote
Accepted
Sum of two state functions is not path independent
I would venture to offer a simple formal explanation of why the arguments leading to the paradoxical inequality of mixed partial derivatives of the state function are incorrect. There were adequate ...
1
vote
Do liquids typically solidify under enough pressure?
No, there are some substances which never become solids. One example: He. If we have 3He, it will form a Bose-Einstein condensate if I remember correctly.
1
vote
Bird feeder - hydrostatic equilibium
Put the lid on and shut it airtight. If you put a hole in at any level, air will flow in and water will flow out.
The level of the spigot determines the water level if there is no air hole. Water can ...
1
vote
Accepted
Is buoyancy affected by container geometry?
The generally accepted answer is "no", simply by application of Archimedes buoyancy principle, but there are limits.
Firstly, if you make your container long enough and thin enough, and ...
1
vote
Enthalpy of a Van der Waals gas continuation
If you know the initial and final states of the gas, it is easier to get the enthalpy change for a VDW gas by working with the internal energy change $\Delta U$ than $\Delta H$. This is because the ...
1
vote
Enthalpy of a Van der Waals gas continuation
Your equation is wrong. It should read $$dH=\left(V-T\left(\frac{\partial V}{\partial T}\right)_P\right)dP$$
You may have to integrate this numerically because of the non-linearity with of the VDW ...
1
vote
Height of a stable droplet on a perfectly wetting surface, shape of a water drop
If I understand your elaborations correctly, your problem is this:
Since the surface is perfectly wetting¹, the contact angle in the typical sense does not matter since there is no point at which the ...
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