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Minimizing the action - particle in a potential well

About change of motion: When an object is in a situation where there is a gradient in the potential then the object will accelerate down the potential gradient. Given that acceleration: the stationary ...
Cleonis's user avatar
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2 votes
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Minimizing the action - particle in a potential well

The principle of least action is poorly named, because often the classical solution corresponds to a saddle point, and not actually a minimum of the action. The condition that you use to derive the ...
Andrew's user avatar
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-1 votes

Why does acceleration seem not to be the gradient of gravitational potential?

In fact, this seems to be a universal and a very logical rule since potential is like energy concentration- masses are accelerated by the negative of the gradient of energy too. To move something of ...
Riad's user avatar
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1 vote
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A man standing in an elevator at the third floor of a building. What is the primary factor that determines the man's kinetic energy?

First of all, kinetic energy (KE) is reference frame dependent. In the frame of the elevator, as long as the man moves with the elevator, the man's KE will always be zero. That said, in any other ...
Bob D's user avatar
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2 votes

A man standing in an elevator at the third floor of a building. What is the primary factor that determines the man's kinetic energy?

The question is a bit misleading so let's go straight to it. If the elevator's speed is $v = 0$, then the mass has no effect whatsoever and $v$ is the "primary factor" causing $K_E = 0$ If ...
Pitchoune's user avatar
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Gravitational potential energy of a water column

The velocity decreases as the column height falls The total energy contained in the column is $mgh \over 2$. So, if we pull the plug and let the column drain out, then the total kinetic energy must be ...
Dale M's user avatar
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3 votes

Gravitational potential energy of a water column

Lets consider a cylinder full of water that is 100 metres high with a cross sectional area of 2 $m^2$ so the volume of water is $200 m^3$ and the mass is 200 tonnes. The initial potential energy of ...
KDP's user avatar
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4 votes

Gravitational potential energy of a water column

If the column of liquid has density $\rho$, cross-sectional area $A$ and height $h$ then its mass is $m = \rho A h$ and its PE is $\displaystyle PE = \frac {mgh} 2 = \rho A g \left( \frac {h^2} 2 \...
gandalf61's user avatar
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6 votes

Gravitational potential energy of a water column

You are correct that if you are considering the GPE of the whole column, then you should take $\frac h2$ because that is the average height of the water. But when considering the water that is coming ...
naturallyInconsistent's user avatar
3 votes

Why is charge on a conductor stable?

Yes that's right, for a charged conductor the electric field outside the surface is directed such as to pull charge off the surface. The reason the charge doesn't leave the surface is to do with what ...
Andrew Steane's user avatar
1 vote

How potential energy is created in Electric dipole?

I understood the things that missing in the concept of potential energy from answers. The thing is represented in the fig. below. Whenever the dipole is placed in the Electric field, it experiences a ...
Rajesh R's user avatar
1 vote

How potential energy is created in Electric dipole?

Probably, the missing information is that, similarly to the case of a force's work, there is also work in the presence of an angular displacement in the presence of a torque (see, for instance, this ...
GiorgioP-DoomsdayClockIsAt-90's user avatar
1 vote

How potential energy is created in Electric dipole?

So, in case of dipole, how does it acquire potential energy without any work done? An external agent needs to do work to rotate the dipole to be perpendicular to the field in order to acquire ...
Bob D's user avatar
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Equilibrium position of a body attached to a spring

The equation $x=mg/k$ gives the position where the mass has attained equilibrium. At this point, the body has attained equilibrium but it isn't necessarily true that the body is at rest. The body ...
XDGamer 849's user avatar
1 vote

Why do we reduce a body to its center of mass when calculating gain/loss of gravitational potential energy?

A real object in a gravitational field has some potential energy (we assume the gravitational field to be uniform over the relatively small size of the object). Now take a point object with zero size ...
Nuclear Hoagie's user avatar
7 votes

Why do we reduce a body to its center of mass when calculating gain/loss of gravitational potential energy?

KDP's answer explains, in elementary terms, why this reduction is acceptable for a uniform rod in a uniform field. This is an elaboration of that answer in case you prefer a more formal derivation. If ...
anon's user avatar
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Hanging mass from spring/ Setting potential to 0

What I am not clear on is what we are actually doing mathematically when we "set U=0". To find the potential energies we are integrating the displacements from a chosen origin. When we ...
KDP's user avatar
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9 votes

Why do we reduce a body to its center of mass when calculating gain/loss of gravitational potential energy?

Consider a mass at height h above the surface and another mass at height (h+L) that are connected by a massless rod. The potential energy of the lower mass is -mgh and the potential energy of the ...
KDP's user avatar
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3 votes

Why do we reduce a body to its center of mass when calculating gain/loss of gravitational potential energy?

When resolving KE of a rigid body the choice of reference point where velocity is calculated and the mass moment of inertia is resolved about are arbitrary. Specifically, a rod of length $\ell$ that ...
John Alexiou's user avatar
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Violation of work-energy theorem (WET) in deriving potential energy (PE) of current-carrying ring in a uniform magnetic field

I am not much of an expert in electromagnetism but the entire reason behind my answer is that you got the WET wrong. I know that many textbooks do not write it properly, so it's not your fault. The ...
Ritzthephysibeast's user avatar
1 vote

Violation of work-energy theorem (WET) in deriving potential energy (PE) of current-carrying ring in a uniform magnetic field

Is it not violation of work-energy theorem (WET) as Work done by external agent is the change in Kinetic Energy and not change in potential energy (PE)? In the work energy theorem the work is net ...
Bob D's user avatar
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1 vote

Relation of field of force to potential energy

According to the multivariable chain rule the total differential of a multivariate function, for example $f(x,y)$, is: $$\mathrm df = \frac{\partial f}{\partial x}\mathrm dx + \frac{\partial f}{\...
Er Jio's user avatar
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1 vote
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Understanding the concept of work and potential energy

Two points: Because of the definition $$\tag1 \text {work}=\Delta \text{potential energy} =\bf F\cdot x$$ where $\bf F$ is the force ($\bf x$ is displacement), the work done would be zero. The ...
joseph h's user avatar
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How does gravitational potential energy work in a very large distance?

Initially, they are millions of light-years apart, with the asteroid slowly moving away from the planet at a velocity exceeding the escape velocity at that distance (1 cm/century). Conventionally, ...
KDP's user avatar
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2 votes

Gravitational potential at any point

When you did the integration (first line in the text box), you've used the limits $0$ to $\infty$. In the "standard" derivation, you integrate from $\infty$ to $0$, because the potential at ...
Allure's user avatar
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