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### Electric field along axis of polarized cylinder

Your first argument makes sense to me, except one point: the surface bound charge density is $P(r)$ on the top and $-P(r)$ at the bottom. Regarding whether the displacement field $\vec{D}$ should be ...
• 448
If you have a $|\uparrow\rangle$ polarizer and a $|\to\rangle$ polarizer. A third polarizer of $45$ degrees in the middle creates superposition of \$\frac{1}{\sqrt{2}}|\uparrow\rangle + \frac{1}{\sqrt{...