2
votes
Accepted
Electric field along axis of polarized cylinder
Your first argument makes sense to me, except one point: the surface bound charge density is $P(r)$ on the top and $-P(r)$ at the bottom.
Regarding whether the displacement field $\vec{D}$ should be ...
- 448
2
votes
This setup works for polarization. Does it work for wavelength?
No.
Light is a combination of oscillating electric and magnetic fields. Polarization is an orientation of light. Think of it as a picket fence. Light gets through if the E field is parallel to the ...
- 27k
2
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This setup works for polarization. Does it work for wavelength?
If you have a $|\uparrow\rangle$ polarizer and a $|\to\rangle$ polarizer. A third polarizer of $45$ degrees in the middle creates superposition of $\frac{1}{\sqrt{2}}|\uparrow\rangle + \frac{1}{\sqrt{...
- 165
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