New answers tagged

0

1) Just flipping the double integral and triple integral basically, the mod term is a scalar and so can be moved so long as it is still integrated over area


0

You might be interested in this. Lets look in case where $\vec E=0$. If you know $q \vec v$, $\vec F$ and $\alpha=\angle(\vec B;q \vec v)$ you can actually find $\vec B$. $$\vec F=q \vec v \times \vec B$$ $$\vec B=\frac{|F|}{ q|v| sin \alpha} \left (\frac{q \vec v cos \alpha}{q |v|}+\frac{q\vec v \times \vec F sin \alpha}{|q\vec v \times \vec F|} \right)= \...


Top 50 recent answers are included