# Tag Info

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This is a Major debating point A lot has been said theoretically about this. You have re-discovered an long running argument in the philosophy of physics. It is often called the "bucket argument" as one of the most famous examples is a bucket of water that is spinning, and so the water level is not flat (bulges up the sides centrifugally) just like your ...

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Earth's gravity is countered by the centrifugal force to a measurable degree. This is one of the reasons the free-fall acceleration is smaller at the equator, compared to the poles.

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Other answers have correctly identified some practical observations that can be used to determine that Earth is rotating (gyroscope; tension in the rocks; Foucault pendulum; just dropping everyday objects, etc.). Here I'll add a remark about the background to the question. The background is an intuition that maybe general relativity suggests it would not be ...

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Earth rotation can be detected using a gyroscope (http://www.tkt.cs.tut.fi/research/nappo_files/Symposium_Gyro_Technology_2010_web.pdf). It looks like the equipment used in the article costs under \$1000 (not including a computer).

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Because the Earth is rotating on it-self, it is not an inertial referential, which means that there are additional fictitious forces acting on objects at rest in the frame of reference. For a spinning referential, the fictitious force is called the Coriolis force, which is responsable of many phenomena such as Foucault pendulum.

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Using what NASA knows you could launch a small missile eastward from the equator and then launch an identical missile westward from the equator. If no spinning, the missiles go the same distance. While this will work, the answer from The Photon seems more practical. lol

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Rotation is not relative and here is a simple though experiment to prove it. Let's suppose that in completely empty space you have two very large rings that are next to each other and spinning in opposite directions relative to each other. You now have two astronauts that are that are standing on the inner surface of the rings, one on each ring. Would each ...

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