# Tag Info

## New answers tagged interference

0

If $D$ is sufficiently large you can suppose the first and second have the phase differencw $\phi$, and the first and the second have phase difference $2\phi$. Then you have $$\sin(\omega t)+\sin(\omega t+\phi)+\sin(\omega t+2\phi)=\sin(\omega t)+\sin(\omega t) \cos\phi)+\cos(\omega t) \sin(\phi)+\sin(\omega t)+\cos(2\phi)+\cos(\omega t)*\sin(2\phi)$$ so ...

2

You are seeing fringes of equal thickness where light from a source is being reflected off the top of the soap film and the bottom of the soap film and then entering your eye to form an interference pattern on the retina of your eye with your eye focussed on the soap film. The condition for a maximum is $2 \, n\, t_{\rm m} = (m+\frac 12) \lambda$ where \$...

0

I think you would not. In the wave theory photon which is moving from you represents as a wave which E-vector oscillates in the flat perpendicular to the you-detector line. And another photon, which is moving from left to right represents as a wave moving from left to right with E-vector oscillates in the flat perpendicular to the line left-right but ...

1

This question blends over into the realm of Physics: Yes, noise-cancelling headphones create what is known as 'anti-sound', which is (virtually) the same sound (and equally loud) as can be heard in the environment, but with an inverted phase. This inverted sound wave indeed cancels out the original sound wave from the environment, resulting in (virtually) ...

1

The interference pattern in the double slit experiment does not result from interactions between electrons. In fact even if you will send the electrons one by one you are still going to get the interference pattern on the screen. In quantum mechanics particles like the electrons are described by their wave functions and from the wave function all the ...

1

You are correct ─ this is an approximation. Unless you introduce some kind of focusing optics to view the fringes, for the rays to interfere they need to reach the same point on the screen, and for this to happen, as you have noted, they need to be at slightly different angles. However, it is important to keep in mind just what the differences are here: ...

Top 50 recent answers are included