New answers tagged coordinate-systems
1
vote
Accepted
How to obtain orthonormal tetrad basis for an infalling observer?
Let me give you the general idea. When constructing an orthonormal frame of an observer, you want to start with the zeroth leg, which is the four-velocity of the observer.
In this case you are looking ...
0
votes
What is the difference between a local and global coordinate transformation?
$x \rightarrow x' = (1+\sigma)x$,
acts identically on each point.
Similarly, if $\epsilon(x) = kx$, then scaling transformation is global as well.
0
votes
Does the singularity travel along the time axis?
In a curved spacetime there is no unique coordinate chart that covers all of spacetime, so the whole notion of "the time axis" is ill-defined. Moreover, the singularity itself is not part of ...
0
votes
Does the singularity travel along the time axis?
We can't observe the singularity but we can observe the event horizon since we are attracted towards it.
This comment reflects a Newtonian approach and neglects GR where the interpretation is that ...
1
vote
The angular momentum of zero mass limit of Kerr metric
The Kerr metric describes a rotating body. $a = J/Mc$ is the angular momentum per unit mass of the body. $a$ characterizes the rate of rotation.
In the limit $M \rightarrow 0$, the metric becomes the ...
1
vote
Why if the metric tensor components are constant then SR applies?
Let me summarize some ideas in the comments and the other answer and add an important point regarding frames that I think is interesting to keep in mind.
In Lorentzian signature, if you go to an ...
1
vote
Why if the metric tensor components are constant then SR applies?
The metric is diagonalizable, yes, and then with further coordinate transformations it can be converted to Minkowski; see, for example, Schutz exercise 6.3 where he guides you through the steps.
3
votes
Partial derivatives vs Covariant derivatives in polar coordinates
As OP correctly points out connections introduce a concept of differentiation of tensor fields or more in general of sections of vector bundles that takes into account how the bases of the fibers ...
5
votes
Partial derivatives vs Covariant derivatives in polar coordinates
Covariant derivatives take into account for both component and basis changes, thereby applicable for curved spaces - where partial derivatives only take component changes into account - is this ...
4
votes
Accepted
Is my understanding of canonical transformations flawed?
Hint: In symplectic notation
$$z^I~=~(q^i,p_i)\qquad\text{and}\qquad Z^I~=~(Q^i,P_i),$$
and assuming no explicit time dependence in the transformation $Z^I=f^I(z)$,
OP has shown that
$$\begin{align}\...
1
vote
Equating 2 sides of EFE
First, note that for scalar functions, the covariant derivative reduces to the partial derivative. So for scalar functions, it is true that if the covariant derivative is zero at a point, then the ...
2
votes
The center of the Schwarzschild black hole
Equation for $r$ in terms of $r'$ (in the question as originally posed) has them the wrong way round. In notation $r$=isotropic, $r'$=Schwarzschild coordinate it should be
$$r' = r (1 + a/r)^2 .$$
...
1
vote
Difference and meaning of index the derivative operator
Here is a brief summary:
In (relativistic) physics, it is standard to adorn a local coordinate $x^{\mu}$ with a superindex.
We define a shorthand notation for the partial derivative $\partial_{\mu}:=...
3
votes
Difference and meaning of index the derivative operator
You can eventually (if you need to) learn a more rigorous treatment later, so let me instead provide a cookbook approach:
An object with an open index means that its value changes when the observer ...
3
votes
The center of the Schwarzschild black hole
The metric in isotropic coordinates (1) and (2) has a (coordinate) singularity at $r=a$. Consequently, there is no a priori relationship between the metric for $r>a$ and $r<a$. They are both ...
3
votes
Accepted
Why can the dot product of two vectors be expressed as a differential?
I would imagine that the simplest way to show this is to note that the position vector $\mathbf x$ can be expressed in either basis:
$$x'^j \hat e_j' = \mathbf x = x^i \hat e_i$$
A given set of ...
1
vote
Why can the dot product of two vectors be expressed as a differential?
First observe, that for any matrix, we can pick up its $i,j$ entry by applying it first to a column vector that is zero apart from $1$ at its $j$'th position and then dotting it into a similar vector ...
3
votes
Accepted
How does the wavefunction transform under an arbitrary change of variables?
TL;DR: As the overall phase of the wavefunction is not physical, OP's question has a non-unique answer that ultimately comes down to a choice of convention. Within a given class of situations we often ...
7
votes
Accepted
Vector addition for differentials in the context of electric potential
I think that your professor is showing the differential vector for infinestimal change in each coordinate component.
The diagrams correspond to cartesian, cylindrical and spherical coordinate systems ...
3
votes
Vector addition for differentials in the context of electric potential
The infinitesimal displacement $d\vec{s}$ is derived from $\vec{s}$.
In cartesian coordinates :
$\vec{s}=x\vec{i}+y\vec{j}+z\vec{k}$
$$d\vec{s}=dx\vec{i}+xd\vec{i}+dy\vec{j}+yd\vec{j}+dz\vec{k}+zd\vec{...
1
vote
Vector addition for differentials in the context of electric potential
The diagrams are slightly misleading, because the infinitesimal changes in angular quantities are shown as being quite large. It may be more helpful to draw separate diagrams showing how $\vec{s}$ ...
0
votes
Accepted
Direction of Area Vector of a simple 2D figure
For a open surface, it is usually in that direction which make acute angle with electric field.
1
vote
Time dilation and understanding which is $\Delta t$ and which is proper time $\tau$
superman is not at rest
There is no preferential frame in relativity. The problem supposes both Louis frame and Superman frame as inertial, with a relative velocity of $0.7$c.
The two events (say ...
0
votes
Time dilation and understanding which is $\Delta t$ and which is proper time $\tau$
Superman's wrist watch is at rest with respect to superman. So the time range measured by superman's wrist watch is smaller (i.e. the time runs slower for superman and for his watch) than the ...
1
vote
Time dilation and understanding which is $\Delta t$ and which is proper time $\tau$
I've always found talk of an observer confusing in Special Relativity. Much clearer, in my opinion, to use the idea of an inertial frame of reference (frame, for short).
The proper time between two ...
0
votes
Time dilation and understanding which is $\Delta t$ and which is proper time $\tau$
Whatever Superman does, he does right where Superman is. Superman kisses Lois goodbye right where Superman is. Twenty hours later in Superman's proper time $\tau$, Superman fixes the space probe right ...
0
votes
Time dilation and understanding which is $\Delta t$ and which is proper time $\tau$
Superman is at rest, in Superman's frame ($S'$).
It's good to assign a frame name to each observer, btw. It increases clarity.
In $S'$, Lois's frame ($S$) is moving at $\beta=-0.7$.
Use events:
$$ E_i ...
0
votes
Time dilation and understanding which is $\Delta t$ and which is proper time $\tau$
According to superman's wrist watch, superman is not moving, and instead Earth and space probe are moving.
0
votes
Inertia tensor but expressed after undergoing rotation
Yes, the interpretation behind
$$ {\rm I}_{\rm world} = R \, {\rm I}_{\rm local} R^\intercal \tag{1}$$
where ${\rm I}_{\rm local}$ is the diagonal matrix representing the MMOI tensor on the body frame,...
1
vote
Direct conversion of cartesian velocity to spherical velocity and vice-versa
Notice that $\frac{d\theta}{dt}$ and $\frac{d\phi}{dt}$ do not have units of velocity (m/s), so right there you have a problem.
Velocity in the $\hat \theta$ direction is "how much distance $ds$ ...
0
votes
Direct conversion of cartesian velocity to spherical velocity and vice-versa
Spherical coordinates describe the position of a point in space in terms of a radius and two angles. Depending on the convention this looks like
$$ \vec{p} = \pmatrix{x \\ y \\ z} = \pmatrix{ r \cos \...
1
vote
General Relativity manipulating tensors, tensor indices meaning
About the first part, you nearly answered your own question: it is indeed exactly because the definition of tensors arises naturally out of multilinear maps such as $t(e^a,e^b)$ that the order of ...
1
vote
Accepted
Direct conversion of cartesian velocity to spherical velocity and vice-versa
This is one of those things that will, upon closer inspection, turn out to be horrible and confusing. Let us compute some stuff, with suggestive notation chosen to make the understanding easier.
...
0
votes
Completeness of radial null geodesics in spacetime of Schwarzschild interior solution
What I was missing is the notion of analytical continuation. While the coordinate is $r$ is always positive geodesics should be continued to the antipodal direction $\theta \rightarrow \pi-\theta,~~~\...
0
votes
Find canonical transformation for $P$ given canonical transformation for $Q$
TL;DR: The answer depends on the context.
Examples:
If we assume that a canonical transformation here means a symplectomorphism, then indeed OP's method is correct: the determinant of the Jacobian is ...
0
votes
Accepted
Components of velocity 3-vector of light in spherical coordinates
$$v_r = c\\v_\vartheta=\vartheta_0\\v_\varphi=\varphi_0$$
Basically by definition, or visual inspection of how the relations are meant to work.
2
votes
Accepted
Kinetic equation material derivative
Using the coordinate system in Fig 5.1, the electric field can be written as:
\begin{equation}
\mathbf{E} = E\left(\cos \vartheta \hat{e}_v - \sin \vartheta \hat{e}_\vartheta \right).
\end{equation}
...
0
votes
Accepted
ADM decomposition incompatible with black hole?
In general, one needs to use a set of horizon-penetrating coordinates. These can be illustrated using a Penrose diagram of a Schwarzschild black hole:
(If you do not know what a Penrose diagram is, ...
-1
votes
ADM decomposition incompatible with black hole?
I feel like it should be improbable to decompose a black hole in these constraints. Given that that the space like hypersurfaces cannot circumvent the singularity in the black hole metric, it would ...
Top 50 recent answers are included
Related Tags
coordinate-systems × 2803general-relativity × 721
special-relativity × 555
metric-tensor × 487
differential-geometry × 429
homework-and-exercises × 387
classical-mechanics × 369
inertial-frames × 347
reference-frames × 335
spacetime × 261
vectors × 247
lagrangian-formalism × 224
newtonian-mechanics × 214
hamiltonian-formalism × 212
tensor-calculus × 166
phase-space × 165
observers × 155
black-holes × 141
kinematics × 123
covariance × 114
differentiation × 112
quantum-mechanics × 94
time × 80
conventions × 78
vector-fields × 71