# Tag Info

### The value of $g$ in free fall motion on earth

$$F=-G\frac{Mm}{r^2}$$ $$\frac{F}{m}=-G\frac{M}{r^2}$$ $$a=-G\frac{M}{r^2}$$ Force divided by mass is by definition acceleration. This is denoted as g, as in, the acceleration due to gravity For the ...

### The value of $g$ in free fall motion on earth

You can see that $g$ has units of acceleration, namely $\frac {m}{s^2}$ or $\frac {m}{s} \left (\frac 1s \right )$. Last form gives an easy interpretation,- speed change per 1 second. Additionally, ...
1 vote

### The value of $g$ in free fall motion on earth

The other guys here (@Thomas Fritsch and @AWanderingMind) are perfectly right, and just to see that: g is an acceleration, and acceleration is change of velocity with time, or velocity per time. Like ...

### The value of $g$ in free fall motion on earth

It means the speed increases by $9.8$ m/s every second. At the beginning (when you release the body) its speed is $0$. After $1$ second the speed is $9.8$ m/s, after $2$ seconds the speed is $19.6$ m/...

### The value of $g$ in free fall motion on earth

It means the speed of the falling body increases with 9.8 m/s each second.
1 vote

### Confusion in coordinate transformation of acceleration vector

The confusion arises because one of the reference frames is moving w.r.t the other one. In your second eq. you are transforming one vector at the seme time, so it is just a coordinate transformation. ...

1 vote

### Confusion regarding pseudo force

To (badly) quote Einstein, pseudo-forces are an ugly way to express the fact that the chosen frame isn't inertial. Say you're in a bus. As long as the bus goes in a straight line with constant ...
1 vote

### Confusion regarding pseudo force

Well, they accelerate to the same rate relative to what? Let say they both have acceleration a relative to an inertial frame. So in the inertial frame there must be a (real, not pseudo) force ...

### If An Instantaneous Force Causes A Charged Particle To Briefly Accelerate, Does Self-inductance Decelerate It?

The brief change in the magnetic field will cause a brief change in the electric field, which I think by Lenz’ law will be in the opposite direction of the particle’s velocity, slowing the particle ...

### If An Instantaneous Force Causes A Charged Particle To Briefly Accelerate, Does Self-inductance Decelerate It?

From Wikipedia Lenz's law states that: The current induced in a circuit due to a change in a magnetic field is directed to oppose the change in flux and to exert a mechanical force which opposes the ...

### Properties of inertial reference frames from different perspectives

Answer to a- the only force acting (as stated friction is not present)is weight of it and the body will have only acceleration due to gravity more accurately saying only have vertical component of ...

### Newton's Principle of Determinacy (intuitive explanation)

According to Arnold, the statement that says we don't need acceleration to predict the future'' is simply an experimental fact. Furthermore, it's said later in Arnold's book that positions and ...
Accepted

If acceleration $a$ is only a function of speed $v$ then the following equations are used to find distance and time \begin{aligned} x - x_0 = \int_{v_0}^v \frac{v}{a}\,{\rm d}v \\ t - t_0 = \... 0 votes ### How do I get the velocity v as a function of position x from the acceleration a as a function of velocity? From a_x = dv_x/dt, using the chain rule, we can write:a_x = \frac{dv}{dx}.\frac{dx}{dt} = \frac{dv}{dx}.v$$And then, from the equation a = f(v),$$f(v) = v.\frac{dv}{dx} \rightarrow \frac{v....
The equation can be written as $$2r\int \frac{\mathrm{d}v}{2rg-v^2}=\int \mathrm{d}t$$ Now we can use the standard integral \int \frac{\mathrm{d}x}{a^2-x^2}=\frac{1}{2a}\ln\left(\frac{a+x}{a-x}\...