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Particle physics is the study of the fundamental forces of nature as they are embodied in the interactions of elementary and composite particles at high energies and short time and distance scales.

1
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Physics departments in the U.S. - and elsewhere - use lots of Linux computers and other Unix flavors, including Solaris, and this gets inherited by the particle physics community, too. It has various …
answered Feb 10 '11 by Luboš Motl
5
votes
Nope, this is just a quasiparticle excitation, like other quasiparticles in condensed matter physics including spinons, chargons, phonons, and others. If they're right, their particular material allow …
answered Apr 20 '12 by Luboš Motl
4
votes
Higgs couplings of the Standard Model are flavor conserving because the separate "flavor numbers" such as $L_\mu$ – the number of muons minus the number of antimuons plus the number of muon neutrinos …
answered Jun 24 '15 by Luboš Motl
0
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The Feynman diagram is completely analogous to the Feynman diagram of the decay of neutron (beta-decay): The muon $\mu^-$ splits to a muon neutrino (there is a mistake on top, it should say $\nu\mu …
answered Aug 14 '14 by Luboš Motl
3
votes
If you consider particular enough models, the assignment of the allowed hypercharges may be easily calculated. The models themselves are constrained by various additional conditions such as anomaly ca …
answered Feb 16 '11 by Luboš Motl
1
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All collections of particles with the total energy and momentum equal to the initial one, total $B=2$, total electric charge $Q=2$, total lepton charge $L=0$, and total spin conserved (or at least int …
answered Nov 10 '11 by Luboš Motl
17
votes
With a sufficient "tolerance", one may of course envision forces that are weaker or much weaker than gravity. Experimentally, one may only improve upper bounds on the strength of the new forces. On t …
answered Jul 18 '14 by Luboš Motl
2
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The Higgs field has a nonzero vacuum expectation value ("vev") $\langle h\rangle =v$. What matters is that it's nonzero; the sign is a matter of conventions. In fact, the Higgs field is a complex one …
answered Jan 28 '16 by Luboš Motl
4
votes
Only superthin metals. The most intense positron beams that people have constructed may send something like 1 billion positrons per second. If the metal is 1 layer of atoms thick, one could perhaps c …
answered Jan 24 '14 by Luboš Motl
3
votes
For generally valid reasons, the amplitudes analytically depend on the momenta and on $s$ in particular. There can't be any "jumps", the simplest discontinuities. Because the processes you enumerated …
answered Jul 14 '13 by Luboš Motl
11
votes
The mass always means the same thing – but in different theories, one uses different equations and other tools to express the mass. Inertial mass $m$ is the quantity expressing "resistance of the obj …
answered Jan 21 '16 by Luboš Motl
2
votes
The CKM matrix describes oscillations but that doesn't mean that it doesn't matter in any other process. The CKM matrix matters pretty much in every process involving quarks. In particular, $d\bar c$ …
answered Jun 25 '16 by Luboš Motl
5
votes
David, your memory is right. You want to use the Drell-Yan-West frame with $q^+=0$, using the light-cone coordinates. In those coordinates, $Q^2=-q^2$ is clearly $q_\perp^2$ because the $q^+ q^-$ term …
answered Feb 23 '11 by Luboš Motl
4
votes
The BBC report is so vague that one can't really determine what was observed. But here is a more coherent report: http://motls.blogspot.com/2010/09/lhc-probably-sees-new-shocking-physics.html The te …
answered Jan 20 '11 by Luboš Motl
13
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Yes, the 6 antiquarks are antiparticles of the 6 quarks – in other words, they're particles of "antimatter". The word "antimatter" sometimes represents just a relative label – antimatter of something …
answered Apr 1 '13 by Luboš Motl

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