Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 87602
1 vote

Why are stress forces considered as acting on a cross-sectional area through a solid?

To find out what is happening within any body, it's common to (mathematically) cut it in half (or at any other point), regard each half as a free body, and examine the conditions that must exist acros …
rdt2's user avatar
  • 682
1 vote

What diameter is used to calculate stress in an elastomer whose cross sectional area changes...

The so-called nominal or engineering stress is force over original area. The true stress is force over current area. Both are useful: the former is easier to calculate, the latter is better relate …
rdt2's user avatar
  • 682
3 votes

Strain-Displacement relationship symmetrization

The anti-symmetric (or skew-symmetric, if you prefer) part of the deformation gradient represents the rigid-body rotation. As a rigid-body motion, it induces no deformation (if inertial effects are …
rdt2's user avatar
  • 682
1 vote

What is the motivation for Mohr's circle?

Mohr's circle is a graphical technique for getting principal stresses. It was useful in the age when most design engineers sat at a drawing board. In an era when most engineers have cellphones and …
rdt2's user avatar
  • 682
4 votes

Strain and stress tensor

@Learning_is_a_mess notes correctly that stress is only symmetric in the absence of internal torque. This is so when the only moments arising are due to forces at a finite distance and so tend to ze …
rdt2's user avatar
  • 682
1 vote

How does stress change through a bar that sharply increases in diameter?

The water analogy is good but think of the water as force and not stress. Equilibrium applies to forces, not stresses and, essentially, what flows in at one end emerges at the other end. In Mechan …
rdt2's user avatar
  • 682